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didieravoaka
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The question can be translated to the following. Is 0 = (2 - p)(2 - q)?didieravoaka wrote:Does the equation y = (x - p)(x - q) intercept the x-axis at (2, 0)?
(1) pq = -8
(2) -2 - p = q
Statement 1:
Try various factors of -8.
p = 1 q = -8 (2 - p)(2 - q) = (1)(6) = 6 No.
p = -4 q = 2 (2 - p)(2 - q) = (2)(0) = 0 Yes.
Insufficient.
Statement 2:
Try various numbers.
Already tried p = -4 q = 2 Yes.
Try p = 1000 q = -1002 (2 - p)(2 - q) will be a huge negative number. No.
Insufficient.
Combined the statements can be used to determine the possible values of p and q. Do you need to do the math given that you have two variables and two distinct equations? Maybe not, but sometimes even with 2 equations you can get multiple possible values for the variables.
Substitute Statement 2 into Statement 1 to get p(-2 - p) = -8.
2p + p² = 8 p² + 2p - 8 = 0 (p + 4)(p - 2) = 0
So if -2 - p = q, then either p = 2 and q = -4 or p = -4 and q = 2.
Either way 0 = (2 - p)(2 - q).
Sufficient.
The correct answer is C.


















