Does the equation y = (x - p)(x - q) intercept the x-axis at the point (2,0)?
(1) pq = -8
(2) -2 - p = q
Since (2, 0) implies that x=2 and y=0, substitute x=2 and y=0 into y = (x - p)(x - q):
0 = (2-p)(2-q).
The resulting equation will be valid if p=2 or q=2.
Question stem, rephrased:
Does p=2 or q=2?
Statement 1: pq = -8
It's possible that p=2 and q=-4, in which case the answer to the question stem is YES.
It's possible that p=1 and q=-8, in which case the answer to the question stem is NO.
Since the answer is YES in the first case but NO in the second case, INSUFFICIENT.
Statement 2: p+q = -2
It's possible that p=2 and q=-4, in which case the answer to the question stem is YES.
It's possible that p=1 and q=-3, in which case the answer to the question stem is NO.
Since the answer is YES in the first case but NO in the second case, INSUFFICIENT.
Statements combined:
Test factor pairs of -8.
In a viable pair, the sum of the two factors will be -2.
Factor pairs of -8:
1, -8
2, -4
4, -2
8, -1.
Only the red pair is viable, implying two cases:
p=2, q=-4
p=-4, q=2.
In each case, the answer to the question stem is YES.
SUFFICIENT.
The correct answer is
C.
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