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Frieda walks 6 feet per second, a pace which is 1/3 as

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by M7MBA » Fri Apr 13, 2018 5:58 am

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Frieda walks 6 feet per second, a pace which is 1/3 as fast as Evita's pace. If Evita's pace is twice as fast as Pablo's then how many feet does Pablo walk in an hour?

A. 129,600
B. 64,800
C. 32,400
D. 3,600
E. 540

The OA is C.

I got confused with the equations. Can anyone help me? Please. I'd be thankful.
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Source: — Problem Solving |

by GMATGuruNY » Fri Apr 13, 2018 6:13 am
M7MBA wrote:Frieda walks 6 feet per second, a pace which is 1/3 as fast as Evita's pace. If Evita's pace is twice as fast as Pablo's then how many feet does Pablo walk in an hour?

A. 129,600
B. 64,800
C. 32,400
D. 3,600
E. 540
Since Frieda's rate is 1/3 Evita's rate, Evita's rate is 3 times Frieda's rate:
3*6 = 18 feet per second.
Since Evita's rate is twice Pablo's rate, Pablo's rate is 1/2 Evita's rate:
(1/2)(18) = 9 feet per second.

How many feet does Pablo walk in an hour?
Since Pablo's rate is 9 feet per second, and 1 hour is the equivalent of 3600 seconds, we get:
Pablo's distance = rt = (9 feet per second)(3600 seconds) = 32,400 feet.

The correct answer is C.
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by Jeff@TargetTestPrep » Sat Jul 14, 2018 8:17 am
M7MBA wrote:Frieda walks 6 feet per second, a pace which is 1/3 as fast as Evita's pace. If Evita's pace is twice as fast as Pablo's then how many feet does Pablo walk in an hour?

A. 129,600
B. 64,800
C. 32,400
D. 3,600
E. 540
The rate of Frieda is 6 feet per second, and that rate is 1/3 as fast as Evita's rate. Thus,

1/3(Evita's rate) = 6

Evita's rate = 18 feet per second

Since Evita's rate is twice as fast as Pablo's rate, Pablo's rate is 18/2 = 9 feet per second.

Thus, Pablo can walk 9 x 3,600 = 32,400 feet in an hour.

(Note: 1 hour = 3,600 seconds)

Answer: C

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