There are 5 chess amateurs playing in Villa's chess club...

Hi LUANDATO,

We're told that there are 5 chess amateurs playing in a tournament and that each chess amateur plays with exactly 4 other amateurs (meaning that each amateur plays each of the other amateurs once). We're asked for the total numbers of chess games played in the tournament. This question can be solved in a couple of different ways. Since the number of chess players is so small, you might find it easiest to just list out the possible matches:

Let's call the chess players A, B, C, D and E

Since each amateur plays each other amateur just once, the matches would be...
AB
AC
AD
AE
BC
BD
BE
CD
CE
DE
10 total matches

Final Answer: A

GMAT assassins aren't born, they're made,
Rich

BTGmoderatorLU wrote:There are 5 chess amateurs playing in Villa's chess club tournament. If each chess amateur plays with exactly 4 other amateurs, what is the total numbers of chess games possible to be played in the tournament?

A) 10
B) 20
C) 40
D) 60
E) 120

The OA is A.

I'm confused with this PS question. Please, can any expert assist me with it? Thanks in advanced.

The total number of games is 5C2 =(5 x 4)/2! = 10 games.

Answer: A