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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## The velocity, density and pressure of a certain fluid... tagged by: BTGmoderatorLU ##### This topic has 1 expert reply and 0 member replies ### Top Member ## The velocity, density and pressure of a certain fluid... The velocity, density and pressure of a certain fluid are related by the equation 5v^2 + P = c, where v is the velocity in meters per second, P is the pressure in Pascals, and c is a constant. If the velocity of this fluid decreases from 10 meters per second to 5 meters per second, by how many pascals does the pressure in the fluid rise? A. 125 B. 250 C. 375 D. 500 E. 625 The OA is C. I'm confused with this DS question. Please, can any expert assist me with it? Thanks in advanced. ### GMAT/MBA Expert Elite Legendary Member Joined 23 Jun 2013 Posted: 9939 messages Followed by: 492 members Upvotes: 2867 GMAT Score: 800 Top Reply Hi LUANDATO, We're told that the Velocity, Density and Pressure of a certain fluid are related by the equation 5(V^2) + P = C, where V is the velocity in meters per second, P is the pressure in Pascals, and C is a constant. We're asked to find the increase in the number of pascals that the fluid will rise when the velocity of this fluid decreases from 10 meters per second to 5 meters per second. This question can essentially be solved by plugging in the values and tracking the results. IF.... V=10, the equation becomes... 5(10^2) + P = C 500 + P = C IF.... V=5, the equation becomes... 5(5^2) + P = C 125 + P = C Since the overall value of 5(V^2) decreases by 375, the "P" has to increase by 375 to 'compensate' for the loss and get the total back up to the constant (C). Final Answer: C GMAT assassins aren't born, they're made, Rich _________________ Contact Rich at Rich.C@empowergmat.com • Award-winning private GMAT tutoring Register now and save up to$200

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