Gmat_mission wrote: ↑Thu May 21, 2020 1:40 am
The time it took car \(A\) to travel 400 miles was 2 hours less than the time it took car \(B\) to travel the same distance. If car \(A\)'s average speed was 10 miles per hour greater than that of car \(B,\) what was car \(B\)'s average speed in miles per hour?
A. 20
B. 30
C. 40
D. 50
E. 80
[spoiler]OA=C[/spoiler]
Source: GMAT Paper Tests
Solution:
We are given that cars A and B both traveled 400 miles and that car A’s average speed was 10 mph greater than that of car B. We can let the rate of car B = r and the rate of car A = r + 10.
Since both cars traveled 400 miles and time = distance/rate, the time of car A is 400/(r+10).
We are also given that it took car A 2 hours less than it took car B to travel the 400 miles. We can set up the following equation:
400/(r+10) + 2 = 400/r
Multiplying the entire equation by r(r+10), we have:
400r + 2(r)(r+10) = 400(r+10)
400r + 2r^2 + 20r = 400r + 4000
2r^2 + 20r - 4000 = 0
r^2 + 10r - 2000 = 0
(r + 50)(r - 40) = 0
r = -50 or r = 40
Since r must be positive, then r = 40.
Alternate Solution:
Let’s test each answer choice:
A) If B’s average speed was 20, then A’s average speed was 20 + 10 = 30.
Is the difference between 400/20 and 400/30 equal to 2? No!
B) If B’s average speed was 30, then A’s average speed was 30 + 10 = 40.
Is the difference between 400/30 and 400/40 equal to 2? No!
C) If B’s average speed was 40, then A’s average speed was 40 + 10 = 50.
Is the difference between 400/40 = 10 and 400/50 = 8 equal to 2? Yes!
Answer: C
