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If the length of an edge of cube \(X\) is twice the length of an edge of cube \(Y,\) what is the ratio of the volume of

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by M7MBA » Wed May 20, 2020 7:21 am

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If the length of an edge of cube \(X\) is twice the length of an edge of cube \(Y,\) what is the ratio of the volume of cube \(Y\) to the volume of cube \(X?\)

(A) 1/2
(B) 1/4
(C) 1/6
(D) 1/8
(E) 1/27

[spoiler]OA=D[/spoiler]

Source: Official Guide
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Re: If the length of an edge of cube \(X\) is twice the length of an edge of cube \(Y,\) what is the ratio of the volume

by anonylfc » Thu May 21, 2020 9:50 am
Area of cube = (side)^3

As side of X is twice of Y-> X=2Y

Ratio of cube Y to cube X will be
=Y^3/X^3
=Y^3/ (2Y)^3
=Y^3/ 8Y^3
=1/8
Hope this helps. Please upvote if you found this helpful !
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Re: If the length of an edge of cube \(X\) is twice the length of an edge of cube \(Y,\) what is the ratio of the volume

by Scott@TargetTestPrep » Mon May 25, 2020 11:13 am
M7MBA wrote: ↑
Wed May 20, 2020 7:21 am
 If the length of an edge of cube \(X\) is twice the length of an edge of cube \(Y,\) what is the ratio of the volume of cube \(Y\) to the volume of cube \(X?\)

(A) 1/2
(B) 1/4
(C) 1/6
(D) 1/8
(E) 1/27

[spoiler]OA=D[/spoiler]

Source: Official Guide
Solution:

Let y = the edge length of cube Y. Thus, 2y = the edge length of cube X. The volume of cube Y is therefore y^3, and that of cube X is (2y)^3 = 8y^3. So the ratio of the volume of cube Y to that of cube X is x^3 / (8x^3) = 1/8.

Answer: D

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