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The figure above shows some of the dimensions of a

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by BTGmoderatorDC » Mon Dec 23, 2019 12:27 am
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The figure above shows some of the dimensions of a triangular plaza with an L-shaped walk along two of its edges. If the width of the walk is 4 feet and the total area of the plaza and walk together is 10,800 square feet, what is the value of x ?

A. 200
B. 204
C. 212
D. 216
E. 225




OA A

Source: Official Guide
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by Jay@ManhattanReview » Mon Dec 23, 2019 12:49 am
BTGmoderatorDC wrote:Image

The figure above shows some of the dimensions of a triangular plaza with an L-shaped walk along two of its edges. If the width of the walk is 4 feet and the total area of the plaza and walk together is 10,800 square feet, what is the value of x ?

A. 200
B. 204
C. 212
D. 216
E. 225

OA A

Source: Official Guide
Area of the walk = x*4 + 100*4 = 400 + 4x
Area of the plaza = 1/2*x*(100 - 4) = 48x

Thus, the total area of the plaza and walk together = 400 + 4x + 48x = 400 + 52x = 10,800 => x = 200 feet

The correct answer: A

Hope this helps!

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Re: The figure above shows some of the dimensions of a

by Scott@TargetTestPrep » Mon Jan 13, 2020 2:34 pm
BTGmoderatorDC wrote: ↑
Mon Dec 23, 2019 12:27 am
 Image

The figure above shows some of the dimensions of a triangular plaza with an L-shaped walk along two of its edges. If the width of the walk is 4 feet and the total area of the plaza and walk together is 10,800 square feet, what is the value of x ?

A. 200
B. 204
C. 212
D. 216
E. 225

OA A

Source: Official Guide
We see that the vertical side of the plaza is 4 feet less than 100, or 96 feet. Therefore, the area of the plaza is ½ * x * 96 = 48x square feet. The area of the walkway is 4(x + 100) = 4x + 400 square feet. Since the total area of the plaza and the walkway is 10,800 square feet, we can create the equation:

48x + 4x + 400 = 10,800

52x = 10,400

x = 200

Answer: A

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Re: The figure above shows some of the dimensions of a

by Brent@GMATPrepNow » Wed Jan 15, 2020 6:40 am
BTGmoderatorDC wrote: ↑
Mon Dec 23, 2019 12:27 am
 Image

The figure above shows some of the dimensions of a triangular plaza with an L-shaped walk along two of its edges. If the width of the walk is 4 feet and the total area of the plaza and walk together is 10,800 square feet, what is the value of x ?

A. 200
B. 204
C. 212
D. 216
E. 225


OA A

Source: Official Guide
Let's add a line to divide the figure into 3 separate shapes
Image

(area of blue triangle) + (area of red rectangle) + (area of green rectangle) = 10,800
Area of triangle = (base)(height)/2
So, we get: (x)(96)/2 + 4x + (4)(100) = 10,800
Simplify: 48x + 4x + 400 = 10,800
Simplify: 52x + 400 = 10,800
Subtract 400 from both sides to get: 52x = 10,400
Solve: x = 10,400/52 = 200

Answer: A

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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