The price of car A increased by 20 percent over the same

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The price of car A increased by 20 percent over the same time period that the price of car B decreased by 20 percent. The reduced price of car B was what percent of the original price of car A?

(1) The increased price of car A is equal to the original price of car B.
(2) The increase in price of car A was 5/6 the decrease in the price of car B.

The OA is D.

Is there a strategic approach to this question? Can anyone help, please? Thanks!

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by GMATGuruNY » Thu Jun 14, 2018 8:01 am

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AAPL wrote:The price of car A increased by 20 percent over the same time period that the price of car B decreased by 20 percent. The reduced price of car B was what percent of the original price of car A?

(1) The increased price of car A is equal to the original price of car B.
(2) The increase in price of car A was 5/6 the decrease in the price of car B.
Car A increased by 20% = 1.2A.
Car B decreased by 20% = 0.8B.
The reduced price of car B was what percent of the original price of car A?
(reduced B)/(original A) = (0.8B)/A = 0.8(B/A).

To answer the question stem, we need to know the value of B/A.
Question stem, rephrased:
What is the value of B/A?

Statement 1:
Since A increased by 20% is equal to the original price of B, we get:
1.2A = B
1.2 = B/A.
SUFFICIENT.

Statement 2:
Since A increases by 20%, the increase in A = 0.2A.
Since B decreases by 20%, the decrease in B = 0.2B.
Since the increase in A is equal to 5/6 the decrease in B, we get:
0.2A = (5/6)(0.2B)
A = (5/6)B
A/B = 5/6
B/A = 6/5.
SUFFICIENT.

The correct answer is D.
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