BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

The population of Linterhast was 3,600 people in 1990

Expert replies
by guerrero » Thu Apr 04, 2013 7:03 am
The population of Linterhast was 3,600 people in 1990 and 4,800 people in 1993. If the population growth rate per thousand is constant, then what will be the population in 1996?

(A) 6,000
(B) 6,400
(C) 7,200
(D) 8,000
(E) 9,600

OA B
Join the discussion
Source: — Problem Solving |

by Brent@GMATPrepNow » Thu Apr 04, 2013 7:19 am
guerrero wrote:The population of Linterhast was 3,600 people in 1990 and 4,800 people in 1993. If the population growth rate per thousand is constant, then what will be the population in 1996?

(A) 6,000
(B) 6,400
(C) 7,200
(D) 8,000
(E) 9,600

OA B
In the 3 years between 1990 and 1993, the population increased by 1200 people.
Since the original population was 3600, we can say the population increased by 1/3 (since 1200/3600 = 1/3)

If the growth rate is constant, then in the 3 years between 1993 and 1996, the population will once again increase by 1/3

1/3 of 4800 = 1600
So, the 1996 population will be 4800 + 1600 = [spoiler]6400 = B[/spoiler]

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by Anju@Gurome » Thu Apr 04, 2013 7:27 am
guerrero wrote:The population of Linterhast was 3,600 people in 1990 and 4,800 people in 1993. If the population growth rate per thousand is constant, then what will be the population in 1996?
Population growth rate per thousand = [(4800 - 3600)/3600]*1000 in 3 years = 1000/3 in 3 years

Hence, from 1993 to 1996, in 3 years population will increase by (4800/1000)*(1000/3) = 4800/3 = 1600

So, final population in 1996 = (4800 + 1600) = 6400

The correct answer is B.
Anju Agarwal
Quant Expert, Gurome

Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.

§ GMAT with Gurome § Admissions with Gurome § Career Advising with Gurome §
Join the discussion

by srcc25anu » Thu Apr 04, 2013 11:33 am
Pop in 1990 = 3600
Pop in 1993 = 4800
Let R be the CONSTANT growth rate each year.

therefore 4800 = 3600 * (1+R)^3
=> (1+R)^3 = 4800 / 3600 = 4/3

Now we have the pop of 1993 as 4800
we have to find the population after 3 years in 1996

Pop in 1996 = 4800 * (1+R)^3
we know (1+R)^3 = 4/3

hence Pop in 1996 = 4800 * 4/3 = 6400
answer B
Join the discussion