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The number of rooms at Hotel G is 10 less than twice the num

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by BTGmoderatorAT » Tue Jan 16, 2018 10:52 pm
The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel H is 425, what is the number of rooms at Hotel G?

(A) 140
(B) 180
(C) 200
(D) 240
(E) 280

OA: E

Is there a strategic approach to this question? . Can any experts help?
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Source: — Problem Solving |

by Jay@ManhattanReview » Wed Jan 17, 2018 2:52 am
ardz24 wrote:The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel H is 425, what is the number of rooms at Hotel G?

(A) 140
(B) 180
(C) 200
(D) 240
(E) 280

OA: E

Is there a strategic approach to this question? . Can any experts help?
Pl. find it here https://www.beatthegmat.com/the-number-o ... 99884.html

Hope this helps!

-Jay
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Manhattan Review GMAT Prep

Locations: New York | Singapore | London | Dubai | and many more...

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by GMATGuruNY » Wed Jan 17, 2018 3:36 am
ardz24 wrote:The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel H is 425, what is the number of rooms at Hotel G?

(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
We can PLUG IN THE ANSWERS, which represent the number of rooms at G.
When the correct answer is plugged in, the number of rooms at G will be 10 less than twice the number of rooms at H.

D: G = 240
Since the total number of rooms at G and H = 425, H = 425-240 = 185.
10 less than twice H = (2*185) - 10 = 360.
Here, G is LESS than the value in blue, implying that the value of G must be BIGGER.

The correct answer is E.

E: G = 280
Since the total number of rooms at G and H = 425, H = 425-280 = 145.
10 less than twice H = (2*145) - 10 = 280.
Success!
G is equal to the value in blue.

Algebra:
Since G is equal to 10 less than twice H, we get:
G = 2H - 10

Since the total number of rooms at G and H is 425, we get:
G + H = 425
H = 425 - G

Substituting H = 425-G into G = 2H - 10, we get:
G = 2(425-G) - 10
G = 850 - 2G - 10
3G = 840
G = 280.
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by DrMaths » Wed Jan 17, 2018 5:24 am
Substitute H (= 425 - G) into G = 2H - 10
to get G = 2(425-G) -10
So, G = 850 -2G - 10
So 3G = 840
then G = 840/3 = 280
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ardz24 wrote:The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel H is 425, what is the number of rooms at Hotel G?

(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
We can also solve the question using 1 variable

Let x = number of rooms at Hotel H

The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H
So, 2x - 10 = number of rooms at Hotel G

The total number of rooms at Hotel G and Hotel H is 425
We can write: x + (2x - 10) = 425
Simplify: 3x - 10 = 425
Solve: x = 145

2x - 10 = number of rooms at Hotel G
So, the number of rooms at Hotel G = 2(145) - 10
= 280

Answer: E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by [email protected] » Wed Jan 17, 2018 10:36 am
Hi ardz24,

We're told that the number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H and that the total number of rooms at Hotel G and Hotel H is 425. We're asked for the number of rooms at Hotel G. This question can be solved by TESTing THE ANSWERS.

To start, we have a total of 425 rooms and we're told that Hotel G has 10 less than TWICE the rooms at Hotel H, so Hotel G clearly has a LOT more rooms than Hotel H does. Thus, we should start with one of the larger answers. Let's TEST Answer D.

IF.... Hotel G has 240 rooms
240 is 10 less than twice (H)
240 = 2H - 10
250 = 2H
125 = H
In this scenario, there would be 240+125 = 365 rooms. This is clearly TOO SMALL though (there are supposed to be 425 rooms), so we need both hotels to have more rooms. There's only one answer that allows for that.... If you want to prove the correct answer though, it would just take a bit more math...

IF.... Hotel G has 280 rooms
280 is 10 less than twice (H)
280 = 2H - 10
290 = 2H
145 = H
In this scenario, there would be 280+145 = 425 rooms. This is an exact match for what we were told, so this MUST be the answer.

Final Answer: E

GMAT assassins aren't born, they're made,
Rich
Contact Rich at [email protected]
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by Scott@TargetTestPrep » Mon Aug 05, 2019 6:12 pm
BTGmoderatorAT wrote:The number of rooms at Hotel G is 10 less than twice the number of rooms at Hotel H. If the total number of rooms at Hotel G and Hotel H is 425, what is the number of rooms at Hotel G?

(A) 140
(B) 180
(C) 200
(D) 240
(E) 280
We can let the number of rooms in hotel G = g and the number of rooms in hotel H = h and create the two equations:

g = 2h - 10

and

g + h = 425

Substituting the first equation for g in the second equation, we have:

2h - 10 + h = 425

3h = 435

h = 145

So g = 2(145) - 10 = 280.

Answer: E

Scott Woodbury-Stewart
Founder and CEO
[email protected]

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