The latest model of space shuttle can achieve a maximum

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The latest model of space shuttle can achieve a maximum speed of 25 miles per second. This maximum speed is how many miles per hour?

A. 1,500
B. 3,600
C. 9,000
D. 15,000
E. 90,000

The OA is E.

Source: Princeton Review

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by Brent@GMATPrepNow » Thu Oct 18, 2018 10:46 am
swerve wrote:The latest model of space shuttle can achieve a maximum speed of 25 miles per second. This maximum speed is how many miles per hour?

A. 1,500
B. 3,600
C. 9,000
D. 15,000
E. 90,000
GIVEN: The shuttle can travel 25 miles in 1 second
So, the shuttle can travel 1500 miles in 60 seconds [if you multiply the travel time by 60, the distance traveled is also multiplied by 60]
In other words, the shuttle can travel 1500 miles in 1 MINUTE [60 seconds = 1 MINUTE]
So, the shuttle can travel 90,000 miles in 60 MINUTES [if you multiply the travel time by 60, the distance traveled is also multiplied by 60]
In other words, the shuttle can travel 90,000 miles in 1 HOUR [60 minutes = 1 HOUR]
In other words, the shuttle's speed = 90,000 mile per hour

Answer: E

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by fskilnik@GMATH » Fri Oct 19, 2018 6:39 am
swerve wrote:The latest model of space shuttle can achieve a maximum speed of 25 miles per second. This maximum speed is how many miles per hour?

A. 1,500
B. 3,600
C. 9,000
D. 15,000
E. 90,000
Source: Princeton Review
\[25\,\,{\text{miles}}\,\,{\text{per}}\,\,{\text{second}}\,\,\,\, = \,\,\,?\,\,\,{\text{mph}}\]
Let´s use UNITS CONTROL, one of the most powerful tools of our method!
\[?\,\, = \,\,\,\frac{{25\,\,{\text{miles}}}}{{1\,\,{\text{second}}}}\,\,\,\left( {\frac{{60\,\,{\text{seconds}}}}{{1\,\,{\text{minute}}}}} \right)\,\,\,\,\left( {\frac{{60\,\,{\text{minutes}}}}{{1\,\,{\text{h}}}}} \right)\,\,\,\,\mathop = \limits^{\left( * \right)} \,\,\,\,90,000\,\,\]
\[\left( * \right)\,\,\,25 \cdot 60 \cdot 60\,\, = \,\,\,25 \cdot 4 \cdot 15 \cdot 4 \cdot 15 = 100 \cdot 225 \cdot 4 = 100 \cdot 900\]

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.
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