The latest model of space shuttle can achieve a maximum speed of 25 miles per second. This maximum speed is how many miles per hour?
A. 1,500
B. 3,600
C. 9,000
D. 15,000
E. 90,000
The OA is E.
Source: Princeton Review
The latest model of space shuttle can achieve a maximum
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GIVEN: The shuttle can travel 25 miles in 1 secondswerve wrote:The latest model of space shuttle can achieve a maximum speed of 25 miles per second. This maximum speed is how many miles per hour?
A. 1,500
B. 3,600
C. 9,000
D. 15,000
E. 90,000
So, the shuttle can travel 1500 miles in 60 seconds [if you multiply the travel time by 60, the distance traveled is also multiplied by 60]
In other words, the shuttle can travel 1500 miles in 1 MINUTE [60 seconds = 1 MINUTE]
So, the shuttle can travel 90,000 miles in 60 MINUTES [if you multiply the travel time by 60, the distance traveled is also multiplied by 60]
In other words, the shuttle can travel 90,000 miles in 1 HOUR [60 minutes = 1 HOUR]
In other words, the shuttle's speed = 90,000 mile per hour
Answer: E
Cheers,
Brent
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\[25\,\,{\text{miles}}\,\,{\text{per}}\,\,{\text{second}}\,\,\,\, = \,\,\,?\,\,\,{\text{mph}}\]swerve wrote:The latest model of space shuttle can achieve a maximum speed of 25 miles per second. This maximum speed is how many miles per hour?
A. 1,500
B. 3,600
C. 9,000
D. 15,000
E. 90,000
Source: Princeton Review
Let´s use UNITS CONTROL, one of the most powerful tools of our method!
\[?\,\, = \,\,\,\frac{{25\,\,{\text{miles}}}}{{1\,\,{\text{second}}}}\,\,\,\left( {\frac{{60\,\,{\text{seconds}}}}{{1\,\,{\text{minute}}}}} \right)\,\,\,\,\left( {\frac{{60\,\,{\text{minutes}}}}{{1\,\,{\text{h}}}}} \right)\,\,\,\,\mathop = \limits^{\left( * \right)} \,\,\,\,90,000\,\,\]
\[\left( * \right)\,\,\,25 \cdot 60 \cdot 60\,\, = \,\,\,25 \cdot 4 \cdot 15 \cdot 4 \cdot 15 = 100 \cdot 225 \cdot 4 = 100 \cdot 900\]
This solution follows the notations and rationale taught in the GMATH method.
Regards,
Fabio.
Fabio Skilnik :: GMATH method creator ( Math for the GMAT)
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