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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## The juice stall at the circus stocked just 2 brands of tagged by: BTGmoderatorLU ##### This topic has 4 expert replies and 0 member replies ### Top Member ## The juice stall at the circus stocked just 2 brands of ## Timer 00:00 ## Your Answer A B C D E ## Global Stats Difficult Source: Princeton Review The juice stall at the circus stocked just 2 brands of orange juice tetra packs. Brand A costs$1 per pack and brand B costs $1.5 per pack. Last week, brand A contributed to m% of stall’s revenue and accounted for n% of sales of juice tetra packs. Which of the following expresses m in terms of n? $$A.\ \frac{100n}{150-n}$$ $$B.\ \frac{200n}{250-n}$$ $$C.\ \frac{200n}{300-n}$$ $$D.\ \frac{250n}{400-n}$$ $$E.\ \frac{300n}{500-n}$$ The OA is C. ### GMAT/MBA Expert GMAT Instructor Joined 22 Aug 2016 Posted: 1817 messages Followed by: 29 members Upvotes: 470 Top Reply BTGmoderatorLU wrote: Source: Princeton Review The juice stall at the circus stocked just 2 brands of orange juice tetra packs. Brand A costs$1 per pack and brand B costs $1.5 per pack. Last week, brand A contributed to m% of stall’s revenue and accounted for n% of sales of juice tetra packs. Which of the following expresses m in terms of n? $$A.\ \frac{100n}{150-n}$$ $$B.\ \frac{200n}{250-n}$$ $$C.\ \frac{200n}{300-n}$$ $$D.\ \frac{250n}{400-n}$$ $$E.\ \frac{300n}{500-n}$$ The OA is C. Say the total number of packs sold = x Thus, the total number of brand A packs sold = nx/100; and the total number of brand B packs sold = x - nx/100 = (100x - nx)/100 = x(100 - n)/100 Sales revenue from the sale of brand A = nx/100 * 1 = nx/100 Sales revenue from the sale of brand B = x(100 - n)/100 * 1.5 = 3x(100 - n)/200 => Total sales revenue from the sale of both the brands = [nx/100 + 3x(100 - n)/200] Since it is given that brand A contributed to m% of stall’s revenue, we have [nx/100] = m% of [nx/100 + 3x(100 - n)/200] [n/100] = m[n/100 + 3(100 - n)/200]/100; x gets cancelled n = m[n/100 + 3(100 - n)/200]; 100 gets cancelled 200n = m(2n + 300 - 3n) m = (200 n)/(300 - n) The correct answer: C Hope this helps! -Jay _________________ Manhattan Review GMAT Prep Locations: New York | Singapore | Doha | Lausanne | and many more... Schedule your free consultation with an experienced GMAT Prep Advisor! Click here. ### GMAT/MBA Expert Elite Legendary Member Joined 23 Jun 2013 Posted: 10106 messages Followed by: 494 members Upvotes: 2867 GMAT Score: 800 Hi All, You might recognize this as a 'lift' of an Official Guide question. You can find that question - and a discussion of how to solve it - here: https://www.beatthegmat.com/what-mistake-am-i-making-in-this-substitution-last-sunday-a-t276293.html GMAT assassins aren't born, they're made, Rich _________________ Contact Rich at Rich.C@empowergmat.com ### GMAT/MBA Expert GMAT Instructor Joined 25 Apr 2015 Posted: 2215 messages Followed by: 17 members Upvotes: 43 BTGmoderatorLU wrote: Source: Princeton Review The juice stall at the circus stocked just 2 brands of orange juice tetra packs. Brand A costs$1 per pack and brand B costs $1.5 per pack. Last week, brand A contributed to m% of stall’s revenue and accounted for n% of sales of juice tetra packs. Which of the following expresses m in terms of n? $$A.\ \frac{100n}{150-n}$$ $$B.\ \frac{200n}{250-n}$$ $$C.\ \frac{200n}{300-n}$$ $$D.\ \frac{250n}{400-n}$$ $$E.\ \frac{300n}{500-n}$$ The OA is C. Let’s let p = the total number of juice tetra packs. Since brand A accounts for n% (or n/100) of the sales of the juice tetra packs, brand B accounts for (100-n)% (or (100 - n)/100) of the the sales of the juice tetra packs. Therefore, we have: Sales of Brand A juice / total sales = fraction of stall revenue from Brand A sales [1 x n/100 x p] / [1 x n/100 x p + 1.5 x (100-n)/100 x p] = m/100 [1 x n/100] / [1 x n/100 + 1.5 x (100-n)/100] = m/100 (n/100)/[n/100 + 1.5(100-n)/100] = m/100 n/[n + 1.5(100 - n)] = m/100 100n/[n + 150 - 1.5n] = m 100n/[150 - 0.5n] = m 200n/[300 - n] = m Answer: C _________________ Scott Woodbury-Stewart Founder and CEO ### GMAT/MBA Expert GMAT Instructor Joined 09 Oct 2010 Posted: 1434 messages Followed by: 31 members Upvotes: 59 BTGmoderatorLU wrote: Source: Princeton Review The juice stall at the circus stocked just 2 brands of orange juice tetra packs. Brand A costs$1 per pack and brand B costs $1.5 per pack. Last week, brand A contributed to m% of stall’s revenue and accounted for n% of sales of juice tetra packs. Which of the following expresses m in terms of n? $$A.\ \frac{100n}{150-n} \,\,\,\,\,\,\, B.\ \frac{200n}{250-n} \,\,\,\,\,\,\, C.\ \frac{200n}{300-n} \,\,\,\,\,\,\, D.\ \frac{250n}{400-n} \,\,\,\,\,\,\, E.\ \frac{300n}{500-n}$$ Let´s explore an AGGRESSIVE PARTICULAR CASE: n = 100 : in this case, only brand A was sold, hence all revenue came from brand A and our FOCUS will be (the TARGET) m =100 (of course)! $\left. \begin{gathered} \left( A \right)\,\,\,\frac{{{{10}^4}}}{{50}} \ne 100 \hfill \\ \left( B \right)\,\,\frac{{2 \cdot {{10}^4}}}{{150}} \ne 100 \hfill \\ \left( C \right)\,\,\frac{{2 \cdot {{10}^4}}}{{200}} = 100\,\,\,\,\, \hfill \\ \left( D \right)\,\,\frac{{25 \cdot {{10}^3}}}{{300}} \ne 100 \hfill \\ \left( E \right)\,\,\frac{{3 \cdot {{10}^4}}}{{400}} \ne 100 \hfill \\ \end{gathered} \right\}\,\,\,\,\,\,\,\,\,\mathop \Rightarrow \limits^{{\text{only}}\,\,{\text{survivor}}\,{\text{!}}} \,\,\,\,\,\,\,\left( C \right)$ This solution follows the notations and rationale taught in the GMATH method. Regards, Fabio. _________________ Fabio Skilnik :: GMATH method creator ( Math for the GMAT) English-speakers :: https://www.gmath.net Portuguese-speakers :: https://www.gmath.com.br • Get 300+ Practice Questions 25 Video lessons and 6 Webinars for FREE Available with Beat the GMAT members only code • FREE GMAT Exam Know how you'd score today for$0

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