The graph of the equation xy = k,

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boomgoesthegmat: Senior | Next Rank: 100 Posts; Posts: 93; Joined: Mon Apr 25, 2016 2:22 pmFollowed by: 1 member; Thanked: 1 times

by boomgoesthegmat » Tue May 03, 2016 2:49 pm

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The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above?

A) I and II
B) I and III
C) II and III
D) II and IV
E) III and IV

OA: D

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Source: Beat The GMAT — Problem Solving | Tue May 03, 2016 2:49 pm

OptimusPrep: Master | Next Rank: 500 Posts; Posts: 410; Joined: Fri Mar 13, 2015 3:36 amFollowed by: 8 members; Location: Worldwide; Thanked: 120 times; GMAT Score:770

by OptimusPrep » Tue May 03, 2016 7:19 pm

boomgoesthegmat wrote:

The graph of the equation xy = k, where k < 0, lies in which two of the quadrants shown above?

A) I and II
B) I and III
C) II and III
D) II and IV
E) III and IV

OA: D

We are given that xy = -ve. This means x and y will have different signs.

Hence when x > 0, y < 0 {Quadrant IV}
And when x < 0, y > 0 {Quadrant II}

Correct Option: D

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[email protected]: Elite Legendary Member; Posts: 10392; Joined: Sun Jun 23, 2013 6:38 pmFollowed by: 511 members; Location: Palo Alto, CA; Thanked: 2867 times; GMAT Score:800

by [email protected] » Mon Mar 12, 2018 5:22 pm

Hi All,

We're told that the graph of the equation (X)(Y) = K, where K < 0. We're asked for the two quadrants in which that graph would lie. This question can be solved by TESTing VALUES.

We're told that K is NEGATIVE. Let's TEST K = -2
(X)(Y) = -2

There are LOTS of different 'pairs' of values for X and Y that would fit this equation (since X and Y aren't necessarily integers). Here are two co-ordinates that are possible:
(X, Y)
(2, -1) --> this is in Quadrant 4
(-2, 1) --> this is in Quadrant 2

Final Answer: D

GMAT assassins aren't born, they're made,
Rich

Contact Rich at [email protected]

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