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If T is a set of 35 consecutive integers, of which 17 are

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by Jay@ManhattanReview » Mon Nov 25, 2019 11:27 pm
BTGmoderatorLU wrote:Source: GMAT Prep

If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

A. -2
B. -1
C. 0
D. 1
E. 2

The OA is C
Since 17 integers are negative, 35 - 17 = 18 are non-negative. We are given that the 35 integers are consecutive, thus, they would start from -17 till 17. So, we have 17 negative integers, one zero, and 17 positive integers.

Thus, the sum of all the integers in T = (-17 - 16 ... -1) + 0 + (1 + 2 + ... + 17) = 0.

The correct answer: C

Hope this helps!

-Jay
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by Scott@TargetTestPrep » Mon Dec 02, 2019 5:58 pm
BTGmoderatorLU wrote:Source: GMAT Prep

If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?

A. -2
B. -1
C. 0
D. 1
E. 2

The OA is C
If 17 of the numbers are negative, then 35 - 17 = 18 numbers are zero or greater. Thus, we have the consecutive integers from -17 to 17 (including 0), and thus, the sum is 0.

Answer: C

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