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100 points for $49 worth of Veritas practice GMATs FREE VERITAS PRACTICE GMAT EXAMS Earn 10 Points Per Post Earn 10 Points Per Thanks Earn 10 Points Per Upvote ## The equation of a circle in the x-y coordinate plane is x^2 tagged by: Max@Math Revolution ##### This topic has 3 expert replies and 0 member replies ### GMAT/MBA Expert ## The equation of a circle in the x-y coordinate plane is x^2 ## Timer 00:00 ## Your Answer A B C D E ## Global Stats Difficult [Math Revolution GMAT math practice question] The equation of a circle in the x-y coordinate plane is x^2+y^2=25. How many points of the form (a,b), where a and b are integers, lie on this circle? A. 4 B. 6 C. 8 D. 10 E. 12 _________________ Math Revolution Finish GMAT Quant Section with 10 minutes to spare. The one-and-only Worldâ€™s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. Only$149 for 3 month Online Course
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Max@Math Revolution wrote:
[Math Revolution GMAT math practice question]

The equation of a circle in the x-y coordinate plane is x^2+y^2=25. How many points of the form (a,b), where a and b are integers, lie on this circle?

A. 4
B. 6
C. 8
D. 10
E. 12
The equation for a circle with its center at the origin and a radius of r is as follows:
xÂ˛ + yÂ˛ = rÂ˛.
Thus, xÂ˛ + yÂ˛ = 25 is a circle with its center at the origin and a radius of 5.

A point on this circle will have integer coordinates in three cases:
Case 1: The radius is horizontal
Case 2: The radius is vertical
Case 3: The radius could serve as the hypotenuse of a 3-4-5 triangle

Coordinate pair options for Case 1:
(5, 0)
(-5, 0)
Total ways = 2

Coordinate pair options for Case 2:
(0, 5)
(0, -5)
Total ways = 2

Coordinate pair options for Case 3:
(3, 4)
(3, -4)
(-3, 4)
(-3, -4)
(4, 3)
(4, -3)
(-4, 3)
(-4, -3)
Total ways = 8

Adding together the 3 cases, we get:
2 + 2 + 8 = 12.

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Max@Math Revolution wrote:
[Math Revolution GMAT math practice question]

The equation of a circle in the x-y coordinate plane is x^2+y^2=25. How many points of the form (a,b), where a and b are integers, lie on this circle?

A. 4
B. 6
C. 8
D. 10
E. 12
$$?\,\,\,:\,\,\,\,\# \,\,\left( {x,y} \right)\,\,\,{\rm{integer}}\,\,{\rm{coordinates}}\,\,{\rm{solutions}}\,\,{\rm{for}}\,\,\,{x^2} + {y^2} = 25$$
$$\left| x \right| = 0\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,\left( {x,y} \right) = \left( {0,5} \right)\,\,\,{\rm{or}}\,\,\,\left( {x,y} \right) = \left( {0, - 5} \right)$$
$$\left| x \right| = 1\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{y^2} = 24 \ne \,\,{\rm{perfect}}\,\,{\rm{square}}\,\,\,\, \Rightarrow \,\,\,\,{\rm{no}}\,\,{\rm{solutions}}\,$$
$$\left| x \right| = 2\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{y^2} = 21 \ne \,\,{\rm{perfect}}\,\,{\rm{square}}\,\,\,\, \Rightarrow \,\,\,\,{\rm{no}}\,\,{\rm{solutions}}\,\,\,$$
$$\left| x \right| = 3\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{y^2} = 16\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\{ \matrix{ \,\left( {x,y} \right) = \left( {3,4} \right)\,\,\,{\rm{or}}\,\,\,\left( {x,y} \right) = \left( {3, - 4} \right) \hfill \cr \,\,\,{\rm{or}} \hfill \cr \,\,\left( {x,y} \right) = \left( { - 3,4} \right)\,\,\,{\rm{or}}\,\,\,\left( {x,y} \right) = \left( { - 3, - 4} \right) \hfill \cr} \right.$$
$$\left| x \right| = 4\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{y^2} = 9\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left\{ \matrix{ \,\left( {x,y} \right) = \left( {4,3} \right)\,\,\,{\rm{or}}\,\,\,\left( {x,y} \right) = \left( {4, - 3} \right) \hfill \cr \,\,\,{\rm{or}} \hfill \cr \,\,\left( {x,y} \right) = \left( { - 4,3} \right)\,\,\,{\rm{or}}\,\,\,\left( {x,y} \right) = \left( { - 4, - 3} \right) \hfill \cr} \right.\,\,$$
$$\left| x \right| = 5\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\,{y^2} = 0\,\,\,\,\,\, \Rightarrow \,\,\,\,\,\left( {x,y} \right) = \left( {5,0} \right)\,\,\,{\rm{or}}\,\,\,\left( {x,y} \right) = \left( { - 5,0} \right)$$

$$? = 12$$

This solution follows the notations and rationale taught in the GMATH method.

Regards,
Fabio.

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We need to find all pairs of integers (a,b) such that a^2 + b^2 = 25. These are:
(5,0), (4,3), (3,4), (0,5), (-3,4), (-4,3), (-5,0), (-4,-3), (-3,-4), (0,-5), (3,-4) and (4,-3).
Thus, there are 12 such points that lie on the circle.

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