BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible val

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Legendary Member
Posts: 1223
Joined: Sat Feb 15, 2020 2:23 pmFollowed by: 1 member
by BTGModeratorVI » Wed Dec 16, 2020 12:37 pm

Timer

00:00

Answers

A

B

C

D

E

Stats

Difficulty—

The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible value of z ?

A. 5
B. 6
C. 7
D. 8
E. 9

Answer: B
Source: official guide
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |

GMAT/MBA Expert

User avatar
GMAT Instructor
Posts: 16207
Joined: Mon Dec 08, 2008 6:26 pmFollowed by: 1268 members
Location: Vancouver, BC
Thanked: 5254 times
GMAT Score:770

Re: The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible

by Brent@GMATPrepNow » Mon Dec 28, 2020 8:17 am
BTGModeratorVI wrote: ↑
Wed Dec 16, 2020 12:37 pm
 The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible value of z ?

A. 5
B. 6
C. 7
D. 8
E. 9

Answer: B
Source: official guide
The average (arithmetic mean) of the positive integers x, y, and z is 3
We can write: (x+y+z)/3 = 3

Multiply both sides of the equation by [m]3[/m] to get: x + y + z = 9

At this point we need to find the greatest possible value of z
Important: Keep in mind that the three numbers are DIFFERENT POSITIVE INTEGERS

Since we know that x+y+z=9, we can MAXIMIZE the value of z by MINIMIZING the values of x and y
We know that x is the smallest value.
Since x must be a positive integer, the smallest possible value of x is 1
Since y must be different from x, the smallest possible value of y is 2
At this point we have maximized the value of z

If x=1 and y=2, then z=6

Answer: B

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 2560
Joined: Sun Oct 29, 2017 2:04 pmFollowed by: 6 members

Re: The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible

by swerve » Mon Dec 28, 2020 4:11 pm
BTGModeratorVI wrote: ↑
Wed Dec 16, 2020 12:37 pm
 The average (arithmetic mean) of the positive integers x, y, and z is 3. If x < y < z, what is the greatest possible value of z ?

A. 5
B. 6
C. 7
D. 8
E. 9

Answer: B
Source: official guide
The smallest positive integer is 1 and the 2nd smallest 2.

So, \(3\cdot 3 = 3+x \Longrightarrow x= 6\).

Therefore, B is the correct answer.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1