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The average (arithmetic mean) of integers \(r, s, t, u\),

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by M7MBA » Sat Nov 30, 2019 4:53 am
The average (arithmetic mean) of integers \(r, s, t, u\), and \(v\) is 100. Are exactly two of the integers greater than 100?

(1) Three of the integers are less than 50.
(2) None of the integers is equal to 100.

[spoiler]OA=E[/spoiler]

Source: Princeton Review
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Source: — Data Sufficiency |

by Jay@ManhattanReview » Wed Dec 04, 2019 12:27 am
M7MBA wrote:The average (arithmetic mean) of integers \(r, s, t, u\), and \(v\) is 100. Are exactly two of the integers greater than 100?

(1) Three of the integers are less than 50.
(2) None of the integers is equal to 100.

[spoiler]OA=E[/spoiler]

Source: Princeton Review
Given that the average (arithmetic mean) of integers \(r, s, t, u\), and \(v\) is 100, we have r + s + t + u + v = 500.

Let's take each statement one by one.

(1) Three of the integers are less than 50.

Say r = s = t = 49, thus, from r + s + t + u + v = 500, we have u + v = 353.

Case 1: Say u = 53, then v = 300 > 100. The answer is no.
Case 2: Say u = 153, then v = 200 > 100. The answer is yes.

No unique answer. Insufficient.

(2) None of the integers is equal to 100.

Certainly insufficient.

(1) and (2) together

Both cases discussed above are applicable here. Insufficient.

The correct answer: E

Hope this helps!

-Jay
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