How many different numbers y are there such that Ay + B = C (A, B, and C are known) ?
The question states that the value of y = (C-B)/A. So, if the value of A is not equal to zero, we can say that y =(C-B)/A, a single value. If the value of A is zero, the value of y is undefined and there are infinite/No numbers in the number system that satisfy the equation.
1. C > B
The statement doesn't speak of A or its value, hence the statement is insufficient to answer the question.
2. A > 1
If the value of A is greater than 1, then we know that A is definitely not equal to 0. So, The value of y = (C-B)/A and y has just one value. Therefore the statement is sufficient to answer the question.
IMO
B