Brent@GMATPrepNow wrote: ↑Wed Mar 11, 2020 3:12 pm
The above diagram shows 3 identical circles placed inside a right triangle so that all 3 circles are tangent to line AB. What is the radius of each circle?
A) 5
B) 6
C) 7
D) 8
E) 10
Answer:
A
Source:
www.gmatprepnow.com
Key property: A line tangent to a circle is perpendicular to the circle's radius at the point of intersection
First, if we add the centers of each triangle as as well as the point E, we get the following:
At this point, if we draw lines from point E to each of the three vertices, look at the following:
At this point we may recognize that: (
area of ∆AEB) + (
area of ∆CEA) + (
area of ∆CEB) =
area of ∆ACB
Area of triangle = (base)(height)/2
So, we get:
(40)(r)/2 +
(30)(5r)/2 +
(50)(r)/2 =
(40)(30)/2
Simplify to get: 20r + 75r + 25r = 600
Simplify: 120r = 600
Solve: r = 600/120 = 5
Answer: A
Cheers,
Brent