moneyman,
product of the first 8 positive integers mean 8 * 7 * 6 * 5* 4* 3 * 2
= 2^3 * 7 * 6 * 2^2 * 3 * 2 = 2^6 * 3 * 5 * 6 * 7

with stmt-1, a can be 2, 4 and 8 with n = 6, 3 and 2. Not suff.

now stmt-2 is saying n = 6 and a^n is a multiple of 2^6 * 3 * 5 * 6 * 7. so it is obvious that a = 2
so imo b.

The problem says that the product of the 8 integers is a multiple of a^n and not the other way around?? any suggestions??

moneyman wrote:The problem says that the product of the 8 integers is a multiple of a^n and not the other way around?? any suggestions??

I sam not getting u maxx. the qs is saying abt -

the product of the first 8 positive integers is a multiple of a^n

and that's why it means 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 and te rest is explained in my previous post.