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terminating decimal

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by Pedros » Wed Feb 24, 2010 11:36 am
There must be another way to solve this other than long division, Hopefully

its E , after 4 minutes of calculations
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by DeepthiRajan » Wed Feb 24, 2010 11:55 am
The answer is E. If the denominator can be expressed as either 2 to the power of n or 5 to the power of n, the number will be a terminating number. Since 128 = 2^7, its a terminating number.
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