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Tara drove at an average speed of 50 miles per hour

Expert replies
by Vincen » Tue Nov 28, 2017 6:31 am
Tara drove at an average speed of 50 miles per hour for the first 50 miles of her trip and then at an average speed of 75 miles per hour for the remaining 50 miles of her trip. If she made no stops during the trip, what was Tara's average speed, in miles per hour, for the entire trip?

(A) 50
(B) 55
(C) 60
(D) 65
(E) 70

The OA is C.

I don't have this PS question clear. How can I find the average speed?
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Source: — Problem Solving |

by GMATGuruNY » Tue Nov 28, 2017 6:56 am
Vincen wrote:Tara drove at an average speed of 50 miles per hour for the first 50 miles of her trip and then at an average speed of 75 miles per hour for the remaining 50 miles of her trip. If she made no stops during the trip, what was Tara's average speed, in miles per hour, for the entire trip?

(A) 50
(B) 55
(C) 60
(D) 65
(E) 70
Since the distance traveled at each speed is THE SAME, the distance can be ANY VALUE.
To make the math easier, let the distance at each speed = the LCM of 50 and 75 = 150 miles.
At a speed of 50mph, the time to travel 150 miles = d/r = 150/50 = 3 hours.
At a speed of 75mph, the time to travel 150 miles = d/r = 150/75 = 2 hours.
Average speed for the whole trip = (total distance)/(total time) = (150+150)/(3+2) = 300/5 = 60mph.

The correct answer is C.
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by Scott@TargetTestPrep » Sat Oct 05, 2019 3:41 pm
Vincen wrote:Tara drove at an average speed of 50 miles per hour for the first 50 miles of her trip and then at an average speed of 75 miles per hour for the remaining 50 miles of her trip. If she made no stops during the trip, what was Tara's average speed, in miles per hour, for the entire trip?

(A) 50
(B) 55
(C) 60
(D) 65
(E) 70

The OA is C.

I don't have this PS question clear. How can I find the average speed?
We can use the following formula:

average speed = (distance 1 + distance 2)/(time 1 + time 2)

We see that time 1 = 1 hour, time 2 = 50/75 = 2/3 hours, and distance 1 = distance 2 = 50 miles. Thus:

average = (50 + 50 )/(1 + 2/3)

average = 100/(5/3) = 300/5 = 60 mph.

Answer: C

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by Mo2men » Mon Oct 07, 2019 4:33 am
GMATGuruNY wrote:
Vincen wrote:Tara drove at an average speed of 50 miles per hour for the first 50 miles of her trip and then at an average speed of 75 miles per hour for the remaining 50 miles of her trip. If she made no stops during the trip, what was Tara's average speed, in miles per hour, for the entire trip?

(A) 50
(B) 55
(C) 60
(D) 65
(E) 70
Since the distance traveled at each speed is THE SAME, the distance can be ANY VALUE.
To make the math easier, let the distance at each speed = the LCM of 50 and 75 = 150 miles.
At a speed of 50mph, the time to travel 150 miles = d/r = 150/50 = 3 hours.
At a speed of 75mph, the time to travel 150 miles = d/r = 150/75 = 2 hours.
Average speed for the whole trip = (total distance)/(total time) = (150+150)/(3+2) = 300/5 = 60mph.

The correct answer is C.
Dear GMATGuru,

You have mentioned before that in some cases =, we can apply that an average speed is little that average arithmetic mean of the two speeds. i.e. average speed < (50+75)/2... then average speed < 62.5 So it is 60.

Is above correct? when can I apply this rule and when I CANNOT?

Thanks
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