Rastis wrote:Can anyone provide a simpler explanation please?
Let me take a shot at trying to explain the solution in a simpler way.
1. The cube1 has 6 faces. 2 faces have area as l*b, 2 faces have area as l*h and 2 faces have area as b*h.
Surface area of the Cube1 is sum of all these areas i.e. 2(l*b)+2(l*h)+2(b*h)
Simplifying 2(l*b)+2(l*h)+2(b*h) = 2[(l*b)+(l*h)2(b*h)] ------>(I)
Let us say the l=b=h=1 for this cube.
Hence Surface area of cube1 is now = 2*3 =6
For Cube2, it is given that l=2l i.e. l=2*1=2 and b and h are same as Cube1.
Substitute l=2, b=1 and h=1 in (I) to get the surface area of Cube2. It comes as 2*5=10.
Hence ratio of Surface area of Cube1:Cube2 = 6/10 = 3/5.
OA should be D.
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