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Bang on target so marvelously, Rahul@99Rahul@gurome wrote:Solution:
I think you need to mention that there is no repetition of digits.
When 1 is in the thousands place, we can have 3! or 6 such numbers by arranging the remaining three digits (2, 5 and 6).
Similarly when 2, 5 and 6 are in the thousands respectively, places there will be 3! or 6 numbers each.
So the sum of all the digits in the thousands place will be 1*6 + 2*6 + 5*6 + 6*6 =14*6 = 84.
Similarly the sum of all digits in hundreds, tens and units place is also 84 each.
So the sum of all numbers formed is 84*1000+84*100+84*10+84 = 93324.
Hi gmatrix,gmatrix wrote:find the sum of all the four digit numbers which are formed by the digits 1,2,5,6
[spoiler]OA:93324[/spoiler]
Awesome!!!!Rahul@gurome wrote:Solution:
I think you need to mention that there is no repetition of digits.
When 1 is in the thousands place, we can have 3! or 6 such numbers by arranging the remaining three digits (2, 5 and 6).
Similarly when 2, 5 and 6 are in the thousands respectively, places there will be 3! or 6 numbers each.
So the sum of all the digits in the thousands place will be 1*6 + 2*6 + 5*6 + 6*6 =14*6 = 84.
Similarly the sum of all digits in hundreds, tens and units place is also 84 each.
So the sum of all numbers formed is 84*1000+84*100+84*10+84 = 93324.
