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by sanju09 » Tue Mar 16, 2010 5:15 am
A school has 378 girl students and 675 boy students. The school is divided into strictly boys or strictly girls sections. All sections in the school have the same number of students. What is the minimum possible number of sections in the school?
(A) 14
(B) 25
(C) 27
(D) 39
(E) 42
Last edited by sanju09 on Tue Mar 16, 2010 5:44 am, edited 1 time in total.
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by kstv » Tue Mar 16, 2010 5:28 am
378 = 14 x 27
625 = 25 X 27
So each section can have 27 students
No of section 14 + 25
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by sanju09 » Tue Mar 16, 2010 5:35 am
kstv wrote:378 = 14 x 27
625 = 25 X 27
So each section can have 27 students
No of section 14 + 25
If I do not edit my post, is 378 + 675 not a possible answer?
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by kstv » Tue Mar 16, 2010 5:38 am
you mean how many students (Plural). You can have 3, 9 students also in each section but whats the point.
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by sanju09 » Tue Mar 16, 2010 5:40 am
kstv wrote:you mean how many students (Plural). You can have 3, 9 students also in each section but whats the point.
So, does the question need any edit that could force us to consider GCD only?
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by rohan_vus » Tue Mar 16, 2010 5:44 am
You may want to say 'minimum possible sections' , this should bring GCD in play
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by sanju09 » Tue Mar 16, 2010 5:47 am
rohan_vus wrote:You may want to say 'minimum possible sections' , this should bring GCD in play
Did it a bit before I found you here. Cool tip!
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by rohan_vus » Tue Mar 16, 2010 5:48 am
Well now i see the question changed to 'mininum possible' by the time i could hit enter

In all seriousness ,my post can be ignored now :| [/img]
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by sanju09 » Tue Mar 16, 2010 5:57 am
rohan_vus wrote:Well now i see the question changed to 'mininum possible' by the time i could hit enter

In all seriousness ,my post can be ignored now :| [/img]
it's not so
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by pardeep_10sharma » Tue Mar 16, 2010 7:56 am
Hi..........
By me we have total no. of students as:- 1053.
Now we can see from poptions that only 27 can be answer bcz ony 7 can give u a multiple which ends in 3 as we need 1053. And rest cannot give unit disit of multiple as 3.............

I think u al must get what i have done.

Ans';- 27
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