Statistics

Please post this in DS section

Ok.

Both a & b together answers the queestion.
So answer choice should be D.

First consider (a),from range alone we could not come to a conclusion.
Then consider (b),from largest value we could not determine the least value.

When we take (a) & (b) together

First consider (b) which says G>H

Let G be 100 & H be 99 which is the maximum number that H can hold to meet G>H

Now consider (b) which says the range of A is smaller than that of B,R<S

Let S be 10 and R be 9 which meets R<S


So,least value for A is (100 - 9) which is 91
least value for B is (99 -10) which is 89

Thus, least value of A is always greater than the least value of B.

You got the qustion right ... just be careful with the choices. when both statements are sufficient, its C

PraveenKumar.Rajan wrote:Both a & b together answers the queestion.
So answer choice should be D.

First consider (a),from range alone we could not come to a conclusion.
Then consider (b),from largest value we could not determine the least value.

When we take (a) & (b) together

First consider (b) which says G>H

Let G be 100 & H be 99 which is the maximum number that H can hold to meet G>H

Now consider (b) which says the range of A is smaller than that of B,R<S

Let S be 10 and R be 9 which meets R<S


So,least value for A is (100 - 9) which is 91
least value for B is (99 -10) which is 89

Thus, least value of A is always greater than the least value of B.

IMO E

what is the OA??

Class A
--------------
g-LA=r

Class B
-------------
h-LB=s

Is LA>LB?

stmt1,

r<s

g-LA<h-LB

We dont know any info abt LA and LB.

Insuff

stmt2,

g>h


r+LA>s+LB

We still don't know any info abt LA and LB.

Combining 1 and 2,

r<s or-r>-s

g>h

-->g-r>h-s

LA>LB

Suff

Pick C