alanforde800Maximus wrote:If 11m -n = p, then which of the following represents the average (arithmetic mean) of m, n, and p, in terms of m?
a) 2m-1
b) 4m
c) 6m
d) m/5
e) 6m/5
p = 11m - n.
Let m=3 and n=0, with the result that p = (11*3) - 0 = 33.
Average of m, n and p = (3+0+33)/3 = 12. This is our target.
Now plug m=3 into the answer choices to see which yields our target of 12.
Only
B works:
4m = 4*3 = 12.
The correct answer is
B.
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