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by alanforde800Maximus » Sat Sep 17, 2016 1:22 am
If 11m -n = p, then which of the following represents the average (arithmetic mean) of m, n, and p, in terms of m?

a) 2m-1
b) 4m
c) 6m
d) m/5
e) 6m/5

Please assist with above problem.
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by GMATGuruNY » Sat Sep 17, 2016 2:52 am
alanforde800Maximus wrote:If 11m -n = p, then which of the following represents the average (arithmetic mean) of m, n, and p, in terms of m?

a) 2m-1
b) 4m
c) 6m
d) m/5
e) 6m/5
p = 11m - n.

Let m=3 and n=0, with the result that p = (11*3) - 0 = 33.
Average of m, n and p = (3+0+33)/3 = 12. This is our target.
Now plug m=3 into the answer choices to see which yields our target of 12.
Only B works:
4m = 4*3 = 12.

The correct answer is B.
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by Brent@GMATPrepNow » Sat Sep 17, 2016 3:05 am
alanforde800Maximus wrote:If 11m -n = p, then which of the following represents the average (arithmetic mean) of m, n, and p, in terms of m?

A) 2m-1
B) 4m
C) 6m
D) m/5
E) 6m/5
Another approach:

Average = (m + n + p)/3
Replace p with 11m - n, to get:
Average = [m + n + (11m - n)]/3
= 12m/3
= 4m
= B

Related Video: https://www.gmatprepnow.com/module/gmat ... /video/800

Cheers,
Brent
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