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Source: — Data Sufficiency |
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by Jim@StratusPrep » Mon Jan 30, 2012 9:52 am
1) When you know M is positive the equation can be rearranged to is M/(M-1) < 0 by dividing both sides by the positive M. However, if 0<M<1 this expression is negative, and if M>1 it is positive. INSUFFICIENT

2) See explanation above for 2 examples that this is true and not true. INSUFFICIENT

Together they are not sufficient either, because the .5 and 1.5 are both not integers.

Answer: E
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by mj78ind » Mon Jan 30, 2012 10:02 am
sud21 wrote:Is m^2 / (m-1) < m?

1). M > 0
2). M is not an integer
Another approach:

Rewriting the given equation - m^2/(m-1) - m < 0
=> (m^2 - m^2 + m)/(m-1) < 0
m/(m-1) < 0,
Thus there are two possibilities: m > 0 AND m-1<0 OR m >0 AND m<1, hence 0<m<1
OR m<0 AND m-1>0 OR m<0 AND m>1 NOT POSSIBLE. Hence, the only condition possible is
0<m<1.

Stmt 1 - m could be 0.5 or 2.5. Hence from above INSUFFICIENT.

Stmt 2 - m could be 0.75 or 3.5 with the equation less than or greater than 0. Hence INSUFFICIENT.

Stmt 1 and 2 - m could be 0.8 or 4.1 and again the condition is INSUFFICIENT.

Hence E
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