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Source: — Problem Solving |
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by raulverde » Wed Oct 31, 2007 8:48 am
I get C
RS = 6

Whats the right answer ?
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by ri2007 » Wed Oct 31, 2007 9:10 am
I also get RS = 6.
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by magical cook » Wed Oct 31, 2007 9:43 am
I think I miscalculated.... yes I now got 6 as well. (OA is C) thank you!
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by moneyman » Wed Oct 31, 2007 10:01 pm
The best way to solve this problem would be plugging in answers to check which one gives the area of the square as 81.

The area of a square is s^2 where s is the side of a square.

It is also given that STXU is 1/4th the area of PQXW.

Lets assume RS is 6 then PW will also be 6 and hence the area of PQXW would be 36 and the area of STUX would be 1/4th of 36 which is 9.

The area of STUX is 9 and so each side would be 3.

Now we have the values of RS and ST.Add them up and you will get the value of a side of the big square RTPV which is 6+3=9.

If the value of the side of RTPV is 9 , the area has to be 9^2 which is 81 which satisfies the question.

Please correct me if im wrong.
Maxx
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