In six successive games, a baseball team scored 3 runs once, 6 runs twice, and 9 runs three times.
What was the average (arithmetic mean) number of runs the team scored per game over the six-game period?
A. 8
B. 7
C. 6
D. 5
E. 4
OA is b
Do I need a specific formula to solve this? An Expert pls do justice. Thanks
Standard Deviation.
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Hi Roland2rule,
We're told that in 6 successive games, a baseball team scored 3 runs once, 6 runs twice, and 9 runs three times. We're asked for the average (arithmetic mean) number of runs the team scored per game over the six-game period. Since we're given all of the 'numbers' for this question, we can solve it with a straight-forward calculation:
[(3)(1) + (6)(2) + (9)(3)] / 6 =
42/6 =
7 runs per game
Final Answer: B
GMAT assassins aren't born, they're made,
Rich
We're told that in 6 successive games, a baseball team scored 3 runs once, 6 runs twice, and 9 runs three times. We're asked for the average (arithmetic mean) number of runs the team scored per game over the six-game period. Since we're given all of the 'numbers' for this question, we can solve it with a straight-forward calculation:
[(3)(1) + (6)(2) + (9)(3)] / 6 =
42/6 =
7 runs per game
Final Answer: B
GMAT assassins aren't born, they're made,
Rich
GMAT/MBA Expert
- Scott@TargetTestPrep
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Using the weighted average formula to determine the average number of runs of the six-game period, we have:BTGmoderatorRO wrote:In six successive games, a baseball team scored 3 runs once, 6 runs twice, and 9 runs three times.
What was the average (arithmetic mean) number of runs the team scored per game over the six-game period?
A. 8
B. 7
C. 6
D. 5
E. 4
(3 x 1 + 6 x 2 + 9 x 3)/6 = (3 + 12 + 27)/6 = 42/6 = 7
Answer: B
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