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by BTGmoderatorRO » Sun Jan 07, 2018 7:49 am
In six successive games, a baseball team scored 3 runs once, 6 runs twice, and 9 runs three times.
What was the average (arithmetic mean) number of runs the team scored per game over the six-game period?

A. 8
B. 7
C. 6
D. 5
E. 4

OA is b
Do I need a specific formula to solve this? An Expert pls do justice. Thanks
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by [email protected] » Sun Jan 07, 2018 4:43 pm
Hi Roland2rule,

We're told that in 6 successive games, a baseball team scored 3 runs once, 6 runs twice, and 9 runs three times. We're asked for the average (arithmetic mean) number of runs the team scored per game over the six-game period. Since we're given all of the 'numbers' for this question, we can solve it with a straight-forward calculation:

[(3)(1) + (6)(2) + (9)(3)] / 6 =
42/6 =
7 runs per game

Final Answer: B

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by Scott@TargetTestPrep » Mon Aug 12, 2019 10:43 am
BTGmoderatorRO wrote:In six successive games, a baseball team scored 3 runs once, 6 runs twice, and 9 runs three times.
What was the average (arithmetic mean) number of runs the team scored per game over the six-game period?

A. 8
B. 7
C. 6
D. 5
E. 4
Using the weighted average formula to determine the average number of runs of the six-game period, we have:

(3 x 1 + 6 x 2 + 9 x 3)/6 = (3 + 12 + 27)/6 = 42/6 = 7

Answer: B

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