BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

stamps

Expert replies
by grandh01 » Mon Aug 20, 2012 7:09 pm
Kim bought a total of $2.65 worth of
postage stamps in four denominations.
If she bought an equal number of
5-cent and 25-cent stamps and twice
as many 10-cent stamps as 5-cent
stamps, what is the least number of
1-cent stamps she could have bought ?
(A) 5
(B) 10
(C) 15
(D) 20
(E) 25
Join the discussion
Source: — Problem Solving |

by truplayer256 » Mon Aug 20, 2012 7:17 pm
Assume Kim bought x 5-cent and 25-cent stamps and 2x 10-cent stamps. Let y be the amount of 1-cent stamps bought.

.05(x) + 0.25(x) + 0.20(x) + 0.01(y) = 2.65

y = (2.65 - 0.5(x))*100 = 265 - 50x

In order to minimize y, we must maximize the value of x. The only value of x that works in that case is x = 5.

Therefore y = 265 - 250 = 15 stamps.
Join the discussion

by GMATGuruNY » Tue Aug 21, 2012 12:58 pm
grandh01 wrote:Kim bought a total of $2.65 worth of
postage stamps in four denominations.
If she bought an equal number of
5-cent and 25-cent stamps and twice
as many 10-cent stamps as 5-cent
stamps, what is the least number of
1-cent stamps she could have bought ?
(A) 5
(B) 10
(C) 15
(D) 20
(E) 25
To MINIMIZE the number of 1-cent stamps, we must MAXIMIZE the number of the other types of stamps.

She bought an equal number of 5-cent and 25-cent stamps.
She bought twice as many 10-cent stamps as 5-cent stamps.
In other words, for every 5-cent stamp, one 25-cent stamp and two 10-cent stamps must be bought:
5+25+2(10) = 50.

Thus, the sum of the other types of stamps must be a multiple of 50.
The greatest multiple of 50 less than 265 is 250.
Since 265-250 = 15, 15 cents must be spent on 1-cent stamps.
Thus, the number of 1-cent stamps = 15.

The correct answer is C.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by cypherskull » Wed Aug 22, 2012 10:48 am
Let the number of 5 & 25 cent stamps be x (since they are equal).
So, the no. of 10 cent stamps = 2x.

And let y denote 1 cent stamps.

So,

5x + 25x + 20x + y = 265
=> 50x + y = 265

For y to be minimum, 50x has to be maximized. The largest value in 265 which is a multiple of 50 is 250. Therefore, y = [spoiler]265 - 250 = 15. Ans: C[/spoiler]
Regards,
Sunit

________________________________

Kill all my demons..And my angels might die too!
Join the discussion

by Jeff@TargetTestPrep » Mon Nov 13, 2017 10:18 am
grandh01 wrote:Kim bought a total of $2.65 worth of
postage stamps in four denominations.
If she bought an equal number of
5-cent and 25-cent stamps and twice
as many 10-cent stamps as 5-cent
stamps, what is the least number of
1-cent stamps she could have bought ?
(A) 5
(B) 10
(C) 15
(D) 20
(E) 25
We can create the following variables:

a = number of 1-cent stamps

b = number of 5-cent stamps

c = number of 10-cent stamps

d = number of 25-cent stamps

Thus:

2.65 = 0.01a + 0.05b + 0.10c + 0.25d

and

b = d

and

c = 2b

Thus, we have:

2.65 = 0.01a + 0.05b + 0.10(2b) + 0.25b

2.65 = 0.01a + 0.50b

265 = a + 50b

265 - 50b = a

We want the value of b to be as large as possible and still maintain that the value of 265 - 50b is positive and that value will be the least value of a. We see that if b = 5, then a = 15 (if b > 5, then 265 - 5b, or a, will be negative). Thus, the least value of a is 15.

Answer: C

Jeffrey Miller
Head of GMAT Instruction
[email protected]

Image

See why Target Test Prep is rated 5 out of 5 stars on BEAT the GMAT. Read our reviews
Join the discussion