my $0.02
If a certain positive integer is divided by 9, the remainder is 3. What is the remainder when the integer is divided by 5? i.e. the positive integer K is of the form (9*x)+3, where x is a non negative integer. The question can be rephrased to,
'If Integer K = (9*x)+3(where x is a non negative integer). What is the remainder when K is divided by 5?'
1. If the integer is divided by 45, the remainder is 30
K = (45*y)+30, where Y is a non-negative integer.
K = 5 * ((9*y)+6) = 5 * Positive Integer. If K is a multiple of 5, then 0 is the remainder when it is divided by 5.
Statement 1 is sufficient to answer the question!
2. The integer is divisible by 2
K = (9*x)+3 = 2*L(Where L is a positive Integer)
If x = 1, K = 12 (=2*L, where L = 6). K/5 = 12/5, remainder = 2
If x = 3, K = 30 (=2*L, where L =15). K/5 = 30/5, remainder = 0
Oops! Two different answers.
Statement 2 is insufficient to answer the question!
