Hey, mlaboda:
Nice work...and pretty close. I apologize for the formatting here - square roots are pretty tough to work through in a linear text form - so it's tough to tell exactly where you were slightly off, but here's how I'd break it down:
1) FOIL, just like you did:
First: Sqrt(7 + sqrt48) * Sqrt (7 + sqrt48) = 7 + sqrt48 (NOTE: squaring this term just removes the outer square root)
Outside: Sqrt[(7 + sqrt 48)(7 - sqrt 48)]
Inside: Sqrt [(7 + sqrt 48)(7 - sqrt 48)] (NOTE: same as the Outside term)
Last: Sqrt (7 - sqrt 48) * (Sqrt (7 - sqrt 48) = 7 - sqrt 48
Result: 7 + sqrt 48 + 2[Sqrt[(7 + sqrt 48)(7 - sqrt 48)] + 7 - sqrt 48
2) Combine like terms to simplify:
Here the 7s add together to 14 and the +sqrt48 and -sqrt 48 subtract to 0, so we have:
14 + 2[Sqrt[(7 + sqrt 48)(7 - sqrt 48)]
Now all that's left to deal with is that ugly square root term, which it looks like you handled pretty nicely in your calculations.
3) Use the Difference of Squares rule to work out the parentheses in the middle term:
When I first saw this problem, I knew that the + / - setup would lead here, so I kept working toward being able to use it. Pretty often when you see the opportunity on the horizon to use this rule it will be extremely helpful, so you should keep it in mind as a 'destination' for your calculations.
[sqrt (7 + sqrt 48)(7-sqrt 48)] = 49 - 48 = 1
(and we have two of these since it was multiplied by 2 for the Outside and Inside terms)
So this ends in 2(1) = 2
4) Add that back to the 14 we had from the first/last terms and the correct answer is 16.
Brian Galvin
GMAT Instructor
Chief Academic Officer
Veritas Prep
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