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A Word Problem II

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Source: — Data Sufficiency |

by DanaJ » Thu Feb 12, 2009 7:48 am
You are actually looking for the ratio of defective chips for the four shipments to the total number of chips. This is equal to (2 + 5 + 6 + 4)/(5 000 + 12 000 + 18 000 + 16 000) = 17/51 000 = 1/3 000. This means that 1 chip in 3000 is expected to be defective. Since you have 60 000 chips, you should expect to have 60 000/3 000 = 20 defective chips
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by billzhao » Thu Feb 12, 2009 7:54 am
Thanks. I did a wrong calculation...
Yiliang
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