Some difficult ones .

ok heres for number 1

(10^8-10^2)=10^2*(10^6-1)
(10^7-10^3)=10^3*(10^4-1)

if you approx 10^6-1 as about 10^6 and 10^4-1 as about 10^4

the equation becomes (10^6)/(10^5)

6-5=1 so its 10^1 or 10

if you plug in (1-x) into x^2 you get (1-x)^2 and if you plug it into (1-x)^2 you get (-x)^2 which is the same as (x)^2

if you plug in (x) into x^2 and x into (1-x)^2 you get x^2*(1-x)^2

so with d , you get the same thing if you plug x or 1-x in
answer is d

I got the first explanation and makes sense , but I am not clear with the second one can you please explain it a bit more .

jewbagel wrote:ok heres for number 1

(10^8-10^2)=10^2*(10^6-1)
(10^7-10^3)=10^3*(10^4-1)

if you approx 10^6-1 as about 10^6 and 10^4-1 as about 10^4

the equation becomes (10^6)/(10^5)

6-5=1 so its 10^1 or 10

Could you please explain this:
the equation becomes (10^6)/(10^5)

ok

10^2/10^3 = (1/10^1)

10^6-1 we approx as 10^6
10^4-1 we approx as 10^4

(1/10)*(10^6/10^4) = (10^5/10^4)=10

jewbagel wrote:if you plug in (1-x) into x^2 you get (1-x)^2 and if you plug it into (1-x)^2 you get (-x)^2 which is the same as (x)^2

if you plug in (x) into x^2 and x into (1-x)^2 you get x^2*(1-x)^2

so with d , you get the same thing if you plug x or 1-x in
answer is d

Can you explain this part please .

1.The value of (10^8 - 10^2)/(10^7 - 10^3) is closest to which of the following ?

a. 1
b. 10
c. 10^2
d. 10^3
e. 10^4

For this one we can factor 10^2. So,
Step 1) 10^2(10^6-1)/10^2(10^5 - 10^1)
Step 2) Cancel out the 10^2. This results in: (10^6)-1/(10^5)-10
Step 3) Since this question uses the key word closest, we can deduce that some type of approximation is involved. So basically, it boils down to this: 10^6/10^5 = 10^1
IMO - B

1.The value of (10^8 - 10^2)/(10^7 - 10^3) is closest to which of the following ?

a. 1
b. 10
c. 10^2
d. 10^3
e. 10^4

For this one we can factor 10^2. So,
Step 1) 10^2(10^6-1)/10^2(10^5 - 10^1)
Step 2) Cancel out the 10^2. This results in: (10^6)-1/(10^5)-10
Step 3) Since this question uses the key word closest, we can deduce that some type of approximation is involved. So basically, it boils down to this: 10^6/10^5 = 10^1
IMO - B

rockeyb wrote:

jewbagel wrote:if you plug in (1-x) into x^2 you get (1-x)^2 and if you plug it into (1-x)^2 you get (-x)^2 which is the same as (x)^2

if you plug in (x) into x^2 and x into (1-x)^2 you get x^2*(1-x)^2

so with d , you get the same thing if you plug x or 1-x in
answer is d

Can you explain this part please .

when you plug x , or 1-x in for the variable in the original equation, in this case (x), the answer is the same. Hence f(x)=f(1-x)

For the first question, you dont really need to calculate anything:

(10^8 - 10^2)/(10^7 - 10^3)

Relative to 10^8, 10^2 is very tiny. Think 100,000,000 - 100 = 99,999,900. Not that different from 10^8.

Relative to 10^7, 10^3 is very tiny.

So, in essence, you may think of (10^8 - 10^2)/(10^7 - 10^3) as 10^8/10^7, which equals 10^1 = 10.