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by parul9 » Wed Nov 02, 2011 9:53 am
16 teams.
1st team plays 15 games
2nd team, barring the first team, plays 14 games.
3rd team, barring the 1st and 2nd teams, plays 13 games.
and so on.

So, the solution is actually sum of first 15 numbers.
15*16/2 = 120.

E.
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by vaibhavgupta » Wed Nov 02, 2011 1:07 pm
DanaJ wrote:Source: Veritas Prep

There are 16 teams in a soccer league, and each team plays each of the others once. Given that each game is played by two teams, how many total games will be played?

A) 256
B) 230
C) 196
D) 169
E) 120

Experts: only Veritas Prep experts, please!
simply put 15+14+13+12... and so on till 1 = 120
that's the answer ! :)
If OA is A, IMO B
If OA is B, IMO C
If OA is C, IMO D
If OA is D, IMO E
If OA is E, IMO A

FML!! :/
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by immaculatesahai » Sat Dec 17, 2011 12:06 am
Felt that the easiest approach is just using combinations. There are 16 teams and 2 teams play each game. There total number of combinations is 16C2 = 120
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by ronnie1985 » Fri Mar 30, 2012 9:32 am
16C2 = 120
QED
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by Lifetron » Thu Jul 19, 2012 8:00 am
16c2 = 120

Answer is E
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by Ganesh hatwar » Thu Aug 09, 2012 1:43 am
DanaJ wrote:Source: Veritas Prep

There are 16 teams in a soccer league, and each team plays each of the others once. Given that each game is played by two teams, how many total games will be played?

A) 256
B) 230
C) 196
D) 169
E) 120

Experts: only Veritas Prep experts, please!
I added from 16 to 1 got 136 !

knew something went wrong

tried with 4 teams A,b,c and D

realized 4 can.t be counted so leaving 16 gives 120

E
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by chris558 » Wed Aug 15, 2012 7:08 am
Answer is E!

16 different objects in different combinations of 2 where order does not matter:
16!/(2!14!)=120
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by abuc0112 » Sun Nov 18, 2012 8:27 am
Order doesnt matter so use the combination formula:

nCr = 16!/2!*14!
= 120

OA = E
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by mparakala » Fri Dec 07, 2012 6:19 pm
n(n-1)/2
16*15 / 2 = 120
Ans: E
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by ritzzzr » Wed Feb 20, 2013 12:28 am
Total number of games = 15+14+13+..+0
= (15/2)*16
= 15*8
= 120
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by rajeshsinghgmat » Sun Feb 24, 2013 12:57 am
E in answer.

15+14+13+...+3+2+1

= 15*(15+1)/2

= 120
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by aceacharya » Wed Apr 17, 2013 3:39 pm
E it is
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by Java_85 » Wed Sep 18, 2013 11:05 am
IMO E it is,
15+14+...+1= 15*(Avg=8)= 120
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by arpitatiny » Mon Jan 27, 2014 12:20 am
16P2=120 is the answer because each team palys 2 matchs with each other .It will be a example of permutation not combination.
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by jaspreetsra » Sun Nov 09, 2014 12:59 pm
There are 16 teams in a soccer league, and each team plays each of the others once. Given that each game is played by two teams, how many total games will be played?

A) 256
B) 230
C) 196
D) 169
E) 120
Ans: E

16C2 =(16*15)/2 =120
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