HG10 wrote:If x and y are positive integers and x/y has a remainder of 5, what is the smallest possible value of xy?
As x and y are positive integers, to minimize xy, we have to minimize both x and y.
When x is divided by y, the remainder is 5.
Hence, y must be greater than 5.
Therefore, minimum possible value of y is 6.
Now, possible values of x such that when divided by 6 we get a remainder of 5 are 5, 11, 17 etc. Hence, minimum possible value of x is 5.
Hence, minimum possible value of xy = 5*6 = 30
