BTGmoderatorDC wrote:Six children - A, B, C, D, E, and F - are going to sit in six chairs in a row. Child E must be somewhere to the left of child F. How many possible configurations are there for the children?
A. 60
B. 180
C. 240
D. 360
E. 720
Alternate approach:
Number of options for A = 6. (Any of the 6 chairs.)
Number of options for B = 5. (Any of the 5 remaining chairs.)
Number of options for C = 4. (Any of the 4 remaining chairs.)
Number of options for D = 3. (Any of the 3 remaining chairs.)
Number of options for E and F = 1. (E and F must occupy the two remaining chairs such that E sits to the left of F.)
To combine these options, we multiply:
6*5*4*3*1 = 360.
The correct answer is
D.
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