Simple Interest

gmattester wrote:If x dollars is invested at 10 percent for one year and
y dollars is invested at 8 percent for one year, the
annual income from the 10 percent investment will
exceed the annual income from the 8 percent
investment by $56. If $2,000 is the total amount
invested, how much is invested at 8 percent?
(A) $280
(B) $800
(C) $892
(D) $1,108
(E) $1,200

Here is my strategy but I am not getting answer
P1-P2=56------------1
P1=x+x/10=11x/10
P2=y+8y/100=108y/100

x+ y=2000---------------2
From 1 and 2 find value of x

Sunny22uk wrote:

gmattester wrote:If x dollars is invested at 10 percent for one year and
y dollars is invested at 8 percent for one year, the
annual income from the 10 percent investment will
exceed the annual income from the 8 percent
investment by $56. If $2,000 is the total amount
invested, how much is invested at 8 percent?
(A) $280
(B) $800
(C) $892
(D) $1,108
(E) $1,200

Here is my strategy but I am not getting answer
P1-P2=56------------1
P1=x+x/10=11x/10
P2=y+8y/100=108y/100

x+ y=2000---------------2
From 1 and 2 find value of x

Equation 1 is wrong, as per the question y dollars is invested at 8 percent for one year, the annual income from the 10 percent investment will
exceed the annual income from the 8 percent investment by $56 which means 10%x-8%y=56
Hope this helps