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## simple fraction q, but i got it wrong

This topic has 1 expert reply and 5 member replies
tj123 Senior | Next Rank: 100 Posts
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85 messages

#### simple fraction q, but i got it wrong

Mon Jun 22, 2009 10:27 pm
At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resoltion and still have it pass?

A) 19
B) 17
c) 16
D) 14
e) 13

OA e

I chose B because 2/3 of 40 is 26, which means 14 is the max that can vote against a resolution and still have it pass. why is my methodology wrong

tj123 Senior | Next Rank: 100 Posts
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Tue Jun 23, 2009 9:49 am
thanks i should have rounded up.
that was my mistake
thanks

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Rich.C@EMPOWERgmat.com Elite Legendary Member
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Thu Mar 15, 2018 7:14 pm
Hi All,

In these types of questions, it's important to remember that you can't have a 'fraction of a person.' Thus, you have to pay attention to the question that is ASKED and think in terms of 'whole persons.'

Here, we're told that AT LEAST 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. Since 2/3 of 40 is 26.666666, but we can't have 26.666666 people, we have to round UP to 27. In contrast, 26 people would NOT be enough, since 26/40 = 13/20 = 65% (and not the 66 2/3% minimum that a resolution needs to be passed).

Knowing that it would take AT LEAST 27 people to pass a resolution, the GREATEST number who could vote AGAINST the resolution in this case would be 40-27 = 13.

Final Answer: E

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Rich

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pops Master | Next Rank: 500 Posts
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Mon Jun 22, 2009 10:38 pm
No,
If 14 votes against the resolution then it wont pass since:
26/40 = 0.65 and required is 2/3 = 0.66

BlindVision Master | Next Rank: 500 Posts
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Tue Jun 23, 2009 12:54 am
tj123 wrote:
At least 2/3 of the 40 members of a committee must vote in favor of a resolution for it to pass. What is the greatest number of members who could vote against the resoltion and still have it pass?

A) 19
B) 17
c) 16
D) 14
e) 13

OA e

I chose B because 2/3 of 40 is 26, which means 14 is the max that can vote against a resolution and still have it pass. why is my methodology wrong
If 2/3 = for resolution to pass then 1/3 = resolution to not pass.

The question is asking what is the most votes of "resolution to not pass" and "still have it pass"

40(1/3) = 13.3, rounded to 13

Go E

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rah_pandey Master | Next Rank: 500 Posts
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Tue Jun 23, 2009 3:45 am
I think the confusion is with decimals as 80/3 is not integer. So the thumb rule for passing a resolution
an integer no of votes should be in favour
if by solving we get a fraction than it needs to rounded off to next HIGHER integer even if fraction part is less than 0.5

ssmiles08 Master | Next Rank: 500 Posts
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29 Mar 2009
Posted:
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Tue Jun 23, 2009 5:13 am
Alternatively, you can find the minimum to pass to find the maximum that can vote no.

for the bill to pass at least 2/3 ~ 2/3(40) = 26.667 ~ 27 (b/c 26 votes will still cause a bill to fail)

so the rest of the votes can be no 40-27 = 13. (E)

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