TRIANLGE!!

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marmar29: Senior | Next Rank: 100 Posts; Posts: 61; Joined: Mon Feb 14, 2011 11:39 pm

by marmar29 » Wed Aug 17, 2011 2:52 pm

hello
i need help in a method how to calculate the side of triangle if vertices are given!!
here an example
in tri. abc .. c(4,-4),,b (-3,-3),, a(5,5)so bc is
A) 7.07
B)8.08
c) 9.09
d)10.10
e) 11.11

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Source: Beat The GMAT — Problem Solving | Wed Aug 17, 2011 2:52 pm

MBA.Aspirant: Master | Next Rank: 500 Posts; Posts: 401; Joined: Tue May 24, 2011 1:14 amFollowed by: 5 members; Thanked: 37 times

by MBA.Aspirant » Wed Aug 17, 2011 4:08 pm

use the distance formula:

distance between B (x1,y1) and C (x2,y2) = âˆš [(y2-y1)^2 + (x2-x1)^2]

given two points B (-3,-3) and C (4,-4)

BC = âˆš (-4-(-3))^2 + (4- (-3))^2

= âˆš50

= 7.07

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