hey guys,
i dont know what i am doing wrong with this one
if 2x is 12 less than the sum of 6x and 4y, then x+y = ?
____________________________________________________
the eq should be 2x = (6x+4y) - 12 ??? right ???
if i solve for x - shouldnt it equal x = (-4y + 12) / 4
and now i am lost...
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simple algebra problem
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amising6
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2x=6x+4y+12Gurpinder wrote:hey guys,
i dont know what i am doing wrong with this one
if 2x is 12 less than the sum of 6x and 4y, then x+y = ?
____________________________________________________
the eq should be 2x = (6x+4y) - 12 ??? right ???
if i solve for x - shouldnt it equal x = (-4y + 12) / 4
and now i am lost...
this should be equation
let leave 12 less part we would have 2x=6x+4y
now this 2x is 12 less so this means 6x+4y is 12 more so add 12
solve it now
Ideation without execution is delusion
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deepak_free
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You are right
2x = (6x+4y) - 12
which means
6x + 4y - 2x - 12 =0
(6x - 2x) + 4y = 12
4x + 4y = 12
4(x + y) = 12
x+y = 12/4 = 3
2x = (6x+4y) - 12
which means
6x + 4y - 2x - 12 =0
(6x - 2x) + 4y = 12
4x + 4y = 12
4(x + y) = 12
x+y = 12/4 = 3
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GMATGuruNY
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When a question asks for the value of weird expression such as x+y, try to solve for the weird expression, not for the individual variables.Gurpinder wrote:hey guys,
i dont know what i am doing wrong with this one
if 2x is 12 less than the sum of 6x and 4y, then x+y = ?
____________________________________________________
the eq should be 2x = (6x+4y) - 12 ??? right ???
if i solve for x - shouldnt it equal x = (-4y + 12) / 4
and now i am lost...
Your translation of words into math was perfect:
2x = (6x+4y) - 12
Now let's solve for x+y:
2x = (6x+4y) - 12
0 = 4x + 4y - 12
12 = 4x + 4y
3 = x + y
Success! x +y = 3.
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Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.
As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.
For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
