BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Similar Triangles problem.

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 51
Joined: Sat Oct 16, 2010 9:31 pm
by AndyB » Tue Jan 17, 2012 10:08 am
Hi Friends,

Need help in solving the below problem, I have just started solving the problems so it would be of great help if you could give explanations also.

In the figure given,P is a point on AB, such that AP:PB = 4:3 PQ is parallel to AC and QD is parallel to CP.What is ratio AP:PD ???








Image
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
User avatar
Master | Next Rank: 500 Posts
Posts: 425
Joined: Wed Dec 08, 2010 9:00 amFollowed by: 7 members
Thanked: 56 times
GMAT Score:690

by LalaB » Tue Jan 17, 2012 11:07 am
let AB=7
then AP=4/7*7=4 PB=3/7*7=3

AB/AP=PB/PD OR

AB/PB=AP/PD

AP/PD=7/3

OA please
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1084
Joined: Fri Apr 15, 2011 2:33 pmFollowed by: 21 members
Thanked: 158 times

by pemdas » Tue Jan 17, 2012 12:10 pm
Initially, consider one pair of 2 similar triangles ACP and PQD
Then consider another pair of 2 similar triangles PCB and DQB
Required ratio AP/PD is equal to PB/BD. We know that PB is 3, then PB/BD=3/x provided we set BD as x. AP=4 and AP/PD=4:y provided we set y as PD.

PB=3=x+y, PD=y=3-x, thus, 3/x=4/(3-x).

Solve for x and then find y for the required proportion of 4/y

3/x=4/(3-x), 3(3-x)=4x, 9-3x=4x, 7x=9, x=9/7 and y=3-9/7=12/7

Now proportion 4/y=4 : 12/7= 4* 7/12=7/3 is the answer
Success doesn't come overnight!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 218
Joined: Wed Nov 23, 2011 8:05 pmFollowed by: 4 members
Thanked: 26 times

by chieftang » Tue Jan 17, 2012 1:40 pm
I also came up with 7:3.

Looked at it like this:

Given: AP:PB = 4:3 and the parallel line info, then we know PD:DB=4:3 also.

So PD = 4/7*PB. Call AP 4 & PB 3. Then PD = 12/7

So AP:PD = 4:12/7 = 28/7:12/7 = 28:12 = 7:3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
GMAT Instructor
Posts: 15539
Joined: Tue May 25, 2010 12:04 pmFollowed by: 1906 members
Location: New York, NY
Thanked: 13060 times
GMAT Score:790

by GMATGuruNY » Tue Jan 17, 2012 2:41 pm
Imagel]

Since AC is parallel to PQ, ∆ABC is similar to ∆PBQ.
Since AB:PB = 7:3, AC:PQ = 7:3.

Image

Since CP is parallel to QD, ∆ACP is similar to ∆PQD.
Since AC:PQ = 7:3, AP:PD = 7:3.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 51
Joined: Sat Oct 16, 2010 9:31 pm

by AndyB » Tue Jan 17, 2012 6:26 pm
LalaB wrote:let AB=7
then AP=4/7*7=4 PB=3/7*7=3

AB/AP=PB/PD OR

AB/PB=AP/PD

AP/PD=7/3

OA please

Your solution is right.
The OA is 7:3
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
User avatar
Legendary Member
Posts: 626
Joined: Fri Dec 23, 2011 2:50 amFollowed by: 10 members
Location: Ahmedabad
Thanked: 31 times

by ronnie1985 » Tue Jan 17, 2012 9:36 pm
Using properties of similar triangles,
AP/PB = CQ/QB
Also, CQ/QB = PD/DB=4/3
PD/DB=4/3 =>DB/PD = 3/4=> DB/PD+1 = 7/4=> (DB+PD)/PD = 7/4 = > PB/PD = 7/4
PD = (4/7)PB AND AP = (4/3)PB
AP/PD = 7/3
Follow your passion, Success as perceived by others shall follow you
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 4
Joined: Sat Jun 23, 2012 1:45 am

by Saggii27 » Tue Jul 03, 2012 11:50 am
Since AC is parallel to PQ why it can't be triangle ACP similiar to PBQ.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1