P,Q,R,S

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P,Q,R,S

by harsh.champ » Tue Feb 09, 2010 5:43 am
What is the value of (2P + Q) if it is divisible by 4? (Here, each of P, Q, R and S are positive integers)


A: P x Q = 2.
B: P + Q + R + S = 6 and R > S.

[spoiler]
Using statement A:
Since each of P, Q, R and S are positive integers and
P x Q = 2, then P and Q are either 1 or 2 respectively.
But since it is given that (2P + Q) is divisible by 4, P and Q
cannot be equal to 2 and 1 respectively.
Therefore, P = 1 and Q = 2.
Hence, statement A alone is sufficient to answer the question.
Using statement B:
Please note that neither of P, Q, R and S can take values 6, 5,
4 or 3. (Since, P + Q + R + S = 6)
Now, since R > S, R should be 2 and S should be 1.
Similarly, P = 1 and Q = 2 as (2P + Q) is divisible by 4.
Hence, statement B alone is sufficient to answer the question.[/spoiler]
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by shashank.ism » Tue Feb 09, 2010 5:52 am
harsh.champ wrote:What is the value of (2P + Q) if it is divisible by 4? (Here, each of P, Q, R and S are positive integers)


A: P x Q = 2.
B: P + Q + R + S = 6 and R > S.

[spoiler]
Using statement A:
Since each of P, Q, R and S are positive integers and
P x Q = 2, then P and Q are either 1 or 2 respectively.
But since it is given that (2P + Q) is divisible by 4, P and Q
cannot be equal to 2 and 1 respectively.
Therefore, P = 1 and Q = 2.
Hence, statement A alone is sufficient to answer the question.
Using statement B:
Please note that neither of P, Q, R and S can take values 6, 5,
4 or 3. (Since, P + Q + R + S = 6)
Now, since R > S, R should be 2 and S should be 1.
Similarly, P = 1 and Q = 2 as (2P + Q) is divisible by 4.
Hence, statement B alone is sufficient to answer the question.[/spoiler]
2P+Q is even so q must be even
A.) P x Q = 2. either p or q= 2 q is even q=2 and p=1
B.)P+Q+R+S =6 R>S Q =2or 4 or 6 but 2 is only possible as P, Q,s are also integer
So P+R+S=4
r>S
and combination is 1+1+2=4
so r=2, s=p=1
so p=1,q=2

ans D
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by ajith » Tue Feb 09, 2010 7:29 am
harsh.champ wrote:What is the value of (2P + Q) if it is divisible by 4? (Here, each of P, Q, R and S are positive integers)


A: P x Q = 2.
B: P + Q + R + S = 6 and R > S.
1) P*Q =2

P =2 and Q =1; 2P+Q = 5

or

P= 1 am Q =2 ; 2P+Q =4

Suffiicient


2) P + Q + R + S = 6

R+S =>3

P+Q =< 3

2P+Q is a multiple of 3

Q =1 and P=1 is not possible since 2P+Q is not a multiple of 4
Q=2 P=1 is the ony option

Sufficient



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