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Eddy and Freddy start simultaneously from city \(A\) and they travel to City \(B\) and City \(C\) respectively. Eddy tak

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by Vincen » Tue Oct 06, 2020 7:03 am

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Eddy and Freddy start simultaneously from city \(A\) and they travel to City \(B\) and City \(C\) respectively. Eddy takes \(3\) hours and Freddy takes \(4\) hours to complete the journey. If the distance between City \(A\) and City \(B\) is \(600 \, \text{km}\) and City \(A\) and City \(C\) is \(300 \, \text{km}.\) What is the ratio of their average speed of travel? (Eddy: Freddy)

A. \(\dfrac83\)

B. \(\dfrac38\)

C. \(\dfrac85\)

D. \(\dfrac58\)

E. \(\dfrac53\)

Answer: A

Source: GMAT Club Tests
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Re: Eddy and Freddy start simultaneously from city \(A\) and they travel to City \(B\) and City \(C\) respectively. Eddy

by Scott@TargetTestPrep » Sat Oct 10, 2020 2:32 pm
Vincen wrote: ↑
Tue Oct 06, 2020 7:03 am
 Eddy and Freddy start simultaneously from city \(A\) and they travel to City \(B\) and City \(C\) respectively. Eddy takes \(3\) hours and Freddy takes \(4\) hours to complete the journey. If the distance between City \(A\) and City \(B\) is \(600 \, \text{km}\) and City \(A\) and City \(C\) is \(300 \, \text{km}.\) What is the ratio of their average speed of travel? (Eddy: Freddy)

A. \(\dfrac83\)

B. \(\dfrac38\)

C. \(\dfrac85\)

D. \(\dfrac58\)

E. \(\dfrac53\)

Answer: A

Source: GMAT Club Tests
Solution:

Eddie’s average speed is 600/3 = 200 km/hr. Freddy’s average speed is 300/4 = 75 km/hr. Therefore, the ratio of Eddy’s average speed to that of Freddy is 200/75 = 8/3.

Answer: A

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