BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Sets

Expert replies
by killerdrummer » Tue Mar 26, 2013 5:15 am
If sets S and T are united into a single set, will the mean of this set be smaller than the sum of means of sets S and T ?

1. S and T are one-element sets
2. Neither set S nor set T contains negative numbers
Join the discussion
Source: — Data Sufficiency |

by Brent@GMATPrepNow » Tue Mar 26, 2013 5:57 am
killerdrummer wrote:If sets S and T are united into a single set, will the mean of this set be smaller than the sum of means of sets S and T ?

1. S and T are one-element sets
2. Neither set S nor set T contains negative numbers
Target question: Is the mean of the new set less than the sum of means of sets S and T?

Statement 1: S and T are one-element sets
There are several sets that meet this condition. Here are two:
Case a: S = {2}, T = {3} and new set = {2,3}, in which case the mean of the new set is less than the sum of means of set S and set T
Case b: S = {0}, T = {0} and new set = {0,0}, in which case the mean of the new set is not less than the sum of means of set S and set T
Since we cannot answer the target question with certainty, statement 1 is NOT SUFFICIENT

Statement 2: Neither set S nor set T contains negative numbers
There are several sets that meet this condition. Here are two:
Case a: S = {2}, T = {3} and new set = {2,3}, in which case the mean of the new set is less than the sum of means of set S and set T
Case b: S = {0}, T = {0} and new set = {0,0}, in which case the mean of the new set is not less than the sum of means of set S and set T
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined:
There are several sets that meet both conditions. Here are two:
Case a: S = {2}, T = {3} and new set = {2,3}, in which case the mean of the new set is less than the sum of means of set S and set T
Case b: S = {0}, T = {0} and new set = {0,0}, in which case the mean of the new set is not less than the sum of means of set S and set T
Since we cannot answer the target question with certainty, the combined statements are NOT SUFFICIENT

Answer = E

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by Anju@Gurome » Tue Mar 26, 2013 9:11 am
Have a look at the solution posted by Anurag >> https://www.beatthegmat.com/problem-data ... tml#351638
Anju Agarwal
Quant Expert, Gurome

Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.

§ GMAT with Gurome § Admissions with Gurome § Career Advising with Gurome §
Join the discussion