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by kajcha » Mon Sep 17, 2007 9:13 am
Of the 200 members of a certain association, each member who speaks German also speaks English, and 70 of the members speak only Spanish. If no member speaks all the languages, how many of the members speak two of the three languages?

1) 60 of the members speak only English
2) 20 of the members do not speak any of the three languages

Source Unknown. and I don't know the OA so please explain your answers
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Source: — Data Sufficiency |
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by gmatguy16 » Mon Sep 17, 2007 12:46 pm
to me answer is c.
unique venn-diagram cannot draw online..need to picture yourselves
but mathematically ,

e # only english
x # english+german
y# german +spansh
z # english+spansh
n # none of the languages
only germany not possible since he also know english.

y =0 since if a person knows german and spanish he also knows english but given that none of them know all 3
e+x+y+z+n+70=200
e+x+z+n=130

stat1: e = 60 ,x+z+n=70 ,still dont know x+y ..not sufficient
stat2: n=20 not sufficient
combine 1 and 2, x+y=50 sufficient..guys please correct and let me know
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by gmatguy16 » Mon Sep 17, 2007 12:49 pm
sorry type ...
combine 1 and 2 ,x+z=50 sufficient ...
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by kajcha » Mon Sep 17, 2007 1:01 pm
I also got C.. But I am not sure of OA...

Perhaps we need to wait for some more replies
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Any explainations?

by ashleyd182 » Wed Sep 19, 2007 12:21 am
Hi,

Can anyone provide a detailed/better explaination for the problem?

Thanks,
~ashley
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by samirpandeyit62 » Wed Sep 19, 2007 1:13 am
I agree with gmatguy16, Kajcha , the ans should be C
Regards
Samir
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by [email protected] » Thu Sep 20, 2007 7:53 pm
I also agree with C
I made it woth venn diagram which makes the task easier
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