BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

SET Theory

Expert replies
by iikarthik » Sun Feb 01, 2009 11:41 am
Question # 35
There are 150 students at Seward High School. 66 students play baseball, 45 play basketball, and 42 play soccer. 27 students play exactly two sports, and three students play all three of the sports. How many of the 150 students play none of the three sports?

A) 0

B) 27

C) 30

D) 99

E) 78


Therefore, the number who played at least one sport = the number in Baseball + the number in Basketball + the number in Soccer - number who played exactly two sports -2 *(the number who played all three sports) = 66 + 45 + 42 - 27 - (2 times 3) = 153 - 27- 6 = 120. Since 120 of the students played at least one sport, 150 - 120 = 30 played none of the sports.
***********************************************************
But why is the P(A U B U C) = P(A) + P(B) + P(C) - P(A^B) - P(B^C) - P(C^A) + P(A^B^C) formula not used here.

Pls explain
Join the discussion
Source: — Problem Solving |

by hardik.jadeja » Mon Feb 02, 2009 10:47 am
I used the simple formula

Total = #A + #B + #C - #(A&B) - #(B&C) - #(C&A) - #(A&B&C) - #(A&B&C) + #not member A,B & C.

Last part(not member A,B & C) is what we are interested in.. just put the values and you will get the answer in no time
Join the discussion

by deep2002 » Mon Feb 02, 2009 11:25 am
hardik.jadeja wrote:I used the simple formula

Total = #A + #B + #C - #(A&B) - #(B&C) - #(C&A) - #(A&B&C) - #(A&B&C) + #not member A,B & C.

Last part(not member A,B & C) is what we are interested in.. just put the values and you will get the answer in no time
Does this formula always give you the answer for set problems? I hate sets and can never get the answer....please tell me this is a universon one *puppy eyes*
Join the discussion

by iikarthik » Tue Feb 03, 2009 11:21 am
Hi Jadeja,

The formula didnt work.Thats why i need help
Join the discussion

by dimonya » Tue Feb 03, 2009 11:41 am
who needs formulas :))) this is a logic test not formula application test
Join the discussion